Question

在定义为JSON的列中有以下nvarchar(max)文本：

{"country":
    {"id":642,
    "name":"ROMANIA",
    "nameEn":"ROMANIA",
    "isoAlpha2":"RO",
    "isoAlpha3":"ROU",
    "currencyCode":"RON",
    "requireState":false,
    "addressType":1,
        "streetTypes":
        [
            {"name":"str.","nameEn":"str."},
            {"name":"","nameEn":""},
            {"name":"ale.","nameEn":"ale."},
            {"name":"int.","nameEn":"int."},
            {"name":"fdt.","nameEn":"fdt."},
            {"name":"pta.","nameEn":"pta."},
            {"name":"bld.","nameEn":"bld."},
            {"name":"drm.","nameEn":"drm."},
            {"name":"cal.","nameEn":"cal."},
            {"name":"sos.","nameEn":"sos."}
        ],
    "quarterTypes":[],
    "postCodeFormats":["","NNNNNN"]
    }
}

我想提取ID的值为642，并且使用了以下语句，但是我想知道这是否是正确的方法：

SELECT TOP 1 VALUE
FROM OPENJSON(@jsonBody, '$.country')

如何不使用TOP 1仅提取id元素的值？

Answer 1

更精确的方法是实际指示您要返回ID，而不是假设它始终是第一个值。

SELECT *
FROM OPENJSON(@, N'$.country')
WITH (id int '$.id')

Answer 2

听起来像JSON_VALUE的工作：

SELECT JSON_VALUE(@jsonBody, '$.country.id')

文档中还包含有关如何访问值数组的示例。

SQL Server-OPENJSON解析JSON文本

2 个答案: