Question

我正在尝试在JSON数据上使用OpenJSON，但未按预期产生结果。 field_data中的DB JSON为：

SELECT *
FROM beat_data 
WHERE EXISTS (
  Select *
  FROM OPENJSON(field_data,'$.name') 
  WHERE Value = 'Test'
)

我正在尝试获取名称等于field_data列中的Test的数据。我的查询数据是;

Date d1 = bean.fooDate; // >> from a post request
System.out.println(d1); // >> "Sat May 25 10:00:00 WET 2019"

Date d2 = fooEntity.getFooDate(); // >> from mysql database
System.out.println(d2); // >> "2019-05-25"

我觉得我没有正确使用路径。

Answer 1

您可以尝试使用JSON_VALUE()：

输入：

CREATE TABLE #BeatData (
   JsonColumn nvarchar(max)
)
INSERT INTO #BeatData
   (JsonColumn)
VALUES
   (N'{  
    "name":"Test",
    "Cell-Number":"Test",
    "CNIC":"12112112",
    "Person-Name":"Test",
    "Focal-person-cell-phone":"121212",
    "Focal-person-CNIC":"12121212",
    "Religion":"Test",
    "Total-teachers":"4",
    "Total-students":"37",
    "Total-Hosteled-students":"11",
    "Government-\/-Private":"Govt",
    "Category":"Jamia",
    "Total-Gates":"3",
    "Registration-number":"211121",
    "Security-guard\/watchman":"10",
    "Condition":"Test"
}')

T-SQL：

SELECT *
FROM #BeatData
WHERE JSON_VALUE(JsonColumn, '$.name') = N'Test'

如果要获取JSON数据作为结果集，请尝试以下操作：

SELECT j.*
FROM #BeatData b
CROSS APPLY OPENJSON(b.JsonColumn) WITH (
    name varchar(100) '$.name',
    [Cell-Number] varchar(100) '$."Cell-Number"',
    CNIC varchar(100) '$.CNIC',
    [Person-Name] varchar(100) '$."Person-Name"',
    [Focal-person-cell-phone] varchar(100) '$."Focal-person-cell-phone"',
    [Focal-person-CNIC] varchar(100) '$."Focal-person-CNIC"',
    Religion varchar(100) '$.Religion',
    [Total-teachers] varchar(100) '$."Total-teachers"',
    [Total-students] varchar(100) '$."Total-students"',
    [Total-Hosteled-students] varchar(100) '$."Total-Hosteled-students"',
    [Government-\/-Private] varchar(100) '$."Government-\/-Private"',
    Category varchar(100) '$.Category',
    [Total-Gates] varchar(100) '$."Total-Gates"',
    [Registration-number] varchar(100) '$."Registration-number"',
    [Security-guard\/watchman] varchar(100) '$."Security-guard\/watchman"',
    Condition varchar(100) '$.Condition'
) j
WHERE j.name = N'Test'

如何在SQL中使用OPENJSON

1 个答案: