Question

import threading, socket, sys, time
from queue import Queue

print_lock = threading.Lock()

if len(sys.argv) !=2 :
    print ("Usage: portscan.py <host>")
    sys.exit(1)

host = sys.argv[1]

def scan(port):
    s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
    try:
        con = s.connect((host, port))
        with print_lock:
            print('Port: ' + str(port) + ' is open')
        con.close()
    except:
        pass

def threader():
    while true:
        worker = q.qet()
        scan(worker)
        q.task_done()

q = Queue()

for x in range(100):
    t = threading.Thread(target=threader)
    t.daemon = True
    t.start

for worker in range(1, 1024):
    q.put(worker)

q.join()

当我运行它时，它只是挂起，我没有得到任何结果，它不会给我任何错误。我不知道为什么它不起作用。当我不添加线程功能时，它确实有效。

Answer 1

有三个小错误：

while True
t.start（）
q.get（）

这个更正的代码似乎对我有用：

import threading, socket, sys, time
from queue import Queue

print_lock = threading.Lock()

if len(sys.argv) !=2 :
    print ("Usage: portscan.py <host>")
    sys.exit(1)

host = sys.argv[1]

def scan(port):
    s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
    try:
        con = s.connect((host, port))
        with print_lock:
            print('Port: ' + str(port) + ' is open')
        con.close()
    except:
        pass

def threader():
    while True:
        worker = q.get()
        scan(worker)
        q.task_done()

q = Queue()

for x in range(100):
    t = threading.Thread(target=threader)
    t.daemon = True
    t.start()

for worker in range(1, 1024):
    q.put(worker)

q.join()

Answer 2

for x in range(100):
    t = threading.Thread(target=threader)
    t.daemon = True
    t.start() # <--- you have to call start? or is this a typo

具有多线程的Python端口扫描程序

2 个答案: