Question

我试图在Python中编写一个非常简单的端口扫描程序，直到我决定引入线程才能加快速度。

我想在最后添加一个简短的摘要，其中列出了打开的端口。我把它放在一个名为finish的函数中。但是，自引入线程以来，无论我把它放在哪里，该摘要都显示为我的代码输出中的第一行。

有没有办法可以有效地将线程限制在我需要它的函数中，然后在它到达summary / finish（）之前关闭它，或者我只是犯了一个明显的错误？任何帮助将非常感激。

代码：

from socket import *
from threading import *
screenLock = Semaphore(value=1)

open_ports = []

def scan(ip,port):

    try:
        s = socket(AF_INET, SOCK_STREAM)
        s.connect((ip, port))
        screenLock.acquire()
        print ('Scanning ', ip , 'on port',  port)
        print("Port",port, "is open")
        s.close()
        summary(port)

    except:
        screenLock.acquire()
        print ('Scanning ', ip , 'on port',  port)
        print("Port",port,"is closed")

    finally:
        screenLock.release()
        s.close()

def loop():

    for i in range(1,100):
        ip = '192.168.0.38'
        port = int(i)
        t = Thread(target=scan, args=(ip,int(port)))
        t.start()

    return

def summary(port):

    global open_ports
    open_ports.append(port)
    return      

def main():    
    loop()
    finish()

def finish():

    print('The following ports are open:',open_ports) 


main()

Answer 1

您必须等待所有线程完成：

select i.Id, i.Prayaseeid, i.name, i.Gender, c.Category,
       i.ideadescription, i.Domain, i.ProjectTerms, i.ProjectStartDate, i.Amountsanctioned,
       id.Amount from tb_innovatorDisbursement
       i.projectstatus, i.projectoutcome 
from tb_innovator i left join
     tb_Category c
     on i.category = c.id left join
     tb_innovatorDisbursement id
     on id.tbid = i.dbid and id.applyingforcycle = '1'
where i.tbid = 'TBINO1111A 'and i.applyingforcycle = '1';

在Python端口扫描程序中进行线程化

1 个答案: