Question

我有这样的JSON。我正在使用改造来获得它。第一个索引是来自网站的时间，每4小时更新一次。

这是我的json：

  {
        "2018-01-01-20-00": {
            "donations": 4070,
            "memberCount": 50,
            "members": [
                {
                    "clanRank": 1,
                    "crowns": 0,
                    "donations": 58,
                    "name": "Min",
                    "tag": "L88P2282",
                    "trophies": 4610
                },
                {
                    "clanRank": 2,
                    "crowns": 0,
                    "donations": 76,
                    "name": "matiz",
                    "tag": "G0JVYY0",
                    "trophies": 4443
                },
            ]
        },
        "2018-01-02-00-00": {
        },
    }

正如您所见，时间索引是可变的（可更改的）。

如何为此JSON创建POJO类？

Answer 1

我建议您将此JSON解析为Map<String,SomeExampleClass>，其中SomeExampleClass是您创建的POJO，用于表示与每个日期关联的对象。

例如，我在jsonschema2pojo上使用了JSON的内部部分（我选择了gson作为注释样式）并生成了POJO类。

以下是JSON的一部分：

{
    "donations": 4070,
    "memberCount": 50,
    "members": [
        {
            "clanRank": 1,
            "crowns": 0,
            "donations": 58,
            "name": "Min",
            "tag": "L88P2282",
            "trophies": 4610
        },
        {
            "clanRank": 2,
            "crowns": 0,
            "donations": 76,
            "name": "matiz",
            "tag": "G0JVYY0",
            "trophies": 4443
        }
    ]
}

以下是生成的类，我通过Eclipse添加了toString方法：

package com.example;

import java.util.List;
import com.google.gson.annotations.Expose;
import com.google.gson.annotations.SerializedName;

public class Example {

    @SerializedName("donations")
    @Expose
    private Integer donations;
    @SerializedName("memberCount")
    @Expose
    private Integer memberCount;
    @SerializedName("members")
    @Expose
    private List<Member> members = null;

    public Integer getDonations() {
        return donations;
    }

    public void setDonations(Integer donations) {
        this.donations = donations;
    }

    public Integer getMemberCount() {
        return memberCount;
    }

    public void setMemberCount(Integer memberCount) {
        this.memberCount = memberCount;
    }

    public List<Member> getMembers() {
        return members;
    }

    public void setMembers(List<Member> members) {
        this.members = members;
    }

    @Override
    public String toString() {
        return "Example [donations=" + donations + ", memberCount=" + memberCount + ", members=" + members + "]";
    }

}

这是代表每个成员的类：

package com.example;

import com.google.gson.annotations.Expose;
import com.google.gson.annotations.SerializedName;

public class Member {

    @SerializedName("clanRank")
    @Expose
    private Integer clanRank;
    @SerializedName("crowns")
    @Expose
    private Integer crowns;
    @SerializedName("donations")
    @Expose
    private Integer donations;
    @SerializedName("name")
    @Expose
    private String name;
    @SerializedName("tag")
    @Expose
    private String tag;
    @SerializedName("trophies")
    @Expose
    private Integer trophies;

    public Integer getClanRank() {
        return clanRank;
    }

    public void setClanRank(Integer clanRank) {
        this.clanRank = clanRank;
    }

    public Integer getCrowns() {
        return crowns;
    }

    public void setCrowns(Integer crowns) {
        this.crowns = crowns;
    }

    public Integer getDonations() {
        return donations;
    }

    public void setDonations(Integer donations) {
        this.donations = donations;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public String getTag() {
        return tag;
    }

    public void setTag(String tag) {
        this.tag = tag;
    }

    public Integer getTrophies() {
        return trophies;
    }

    public void setTrophies(Integer trophies) {
        this.trophies = trophies;
    }

    @Override
    public String toString() {
        return "Member [clanRank=" + clanRank + ", crowns=" + crowns + ", donations=" + donations + ", name=" + name
                + ", tag=" + tag + ", trophies=" + trophies + "]";
    }

}

现在这里有一些示例代码将JSON解析为Map：

package gson;

import java.io.IOException;
import java.nio.file.Files;
import java.nio.file.Paths;
import java.util.Map;

import com.example.Example;
import com.google.gson.Gson;
import com.google.gson.reflect.TypeToken;

public class GsonMain {

    public static void main(String[] args) throws IOException {
        Gson gson = new Gson();
        byte[] jsonBytes = Files.readAllBytes(Paths.get("./src/main/java/gson/jsonData.json"));
        String json = new String(jsonBytes);

        Map<String,Example> result = gson.fromJson(json, new TypeToken<Map<String, Example>>(){}.getType());

        System.out.println("RESULTS: "+result);
    }

}

为了测试这个，我使用了以下JSON输入：

{
        "2018-01-01-20-00": {
            "donations": 4070,
            "memberCount": 50,
            "members": [
                {
                    "clanRank": 1,
                    "crowns": 0,
                    "donations": 58,
                    "name": "Min",
                    "tag": "L88P2282",
                    "trophies": 4610
                },
                {
                    "clanRank": 2,
                    "crowns": 0,
                    "donations": 76,
                    "name": "matiz",
                    "tag": "G0JVYY0",
                    "trophies": 4443
                }
            ]
        },
        "2018-01-02-00-00": {
        }
    }

，结果是以下输出：

结果：{2018-01-01-20-00 =示例[捐款= 4070，memberCount = 50， members = [Member [clanRank = 1，crown = 0，donations = 58，name = Min， tag = L88P2282，trophies = 4610]，成员[clanRank = 2，crowns = 0，捐款= 76，姓名= matiz，tag = G0JVYY0，trophies = 4443]]]， 2018-01-02-00-00 =示例[donations = null，memberCount = null，成员=空]}

然后，您可以根据需要在Map中iterate over the entries。

如何获取json的索引并在pojo类中使用它

1 个答案: