DATEDIFF（CURRENT_DATE，updated_at）AS Diff，COUNT（*）

Question

我不能把我的脑袋包裹起来:(

我正在尝试从我的专栏“Diff”中输出3个不同的结果

＆lt; 1＆lt; 3＆lt; 7

到目前为止，这是我的查询：

SELECT DATEDIFF(CURRENT_DATE, updated_at) AS Diff, COUNT(*) FROM Table GROUP BY Diff

但实际上我只需输出3列，金额<1，<3和<7

我希望有人可以提供帮助

Answer 1

使用条件聚合：

SELECT
    COUNT(CASE WHEN DATEDIFF(CURRENT_DATE, updated_at) < 1 THEN 1 END) AS diff_lt_1,
    COUNT(CASE WHEN DATEDIFF(CURRENT_DATE, updated_at) >= 1 AND
                    DATEDIFF(CURRENT_DATE, updated_at) < 3 THEN 1 END) AS diff_1_to_3,
    COUNT(CASE WHEN DATEDIFF(CURRENT_DATE, updated_at) >= 3 AND
                    DATEDIFF(CURRENT_DATE, updated_at) < 7 THEN 1 END) AS diff_3_to_7,
    COUNT(CASE WHEN DATEDIFF(CURRENT_DATE, updated_at) >= 7 THEN 1 END) AS diff_gt_7
FROM Table;

实际上并不清楚您应该在哪个列GROUP BY进行操作。如果您显示示例数据以显示您要执行的操作，我们可以修改上述查询。