pyspark:两个日期列之间的小时差异

时间:2017-11-21 17:54:16

标签: pyspark datediff

我想计算pyspark中两个日期列之间的小时数。 只能找到如何计算日期之间的天数。

dfs_4.show()


+--------------------+--------------------+
|        request_time|            max_time|
+--------------------+--------------------+
|2017-11-17 00:18:...|2017-11-20 23:59:...|
|2017-11-17 00:07:...|2017-11-20 23:59:...|
|2017-11-17 00:35:...|2017-11-20 23:59:...|
|2017-11-17 00:10:...|2017-11-20 23:59:...|
|2017-11-17 00:03:...|2017-11-20 23:59:...|
|2017-11-17 00:45:...|2017-11-20 23:59:...|
|2017-11-17 00:35:...|2017-11-20 23:59:...|
|2017-11-17 00:59:...|2017-11-20 23:59:...|
|2017-11-17 00:28:...|2017-11-20 23:59:...|
|2017-11-17 00:11:...|2017-11-20 23:59:...|
|2017-11-17 00:13:...|2017-11-20 23:59:...|
|2017-11-17 00:42:...|2017-11-20 23:59:...|
|2017-11-17 00:07:...|2017-11-20 23:59:...|
|2017-11-17 00:40:...|2017-11-20 23:59:...|
|2017-11-17 00:15:...|2017-11-20 23:59:...|
|2017-11-17 00:05:...|2017-11-20 23:59:...|
|2017-11-17 00:50:...|2017-11-20 23:59:...|
|2017-11-17 00:40:...|2017-11-20 23:59:...|
|2017-11-17 00:25:...|2017-11-20 23:59:...|
|2017-11-17 00:35:...|2017-11-20 23:59:...|
+--------------------+--------------------+

计算天数:

from pyspark.sql import functions as F
dfs_5 = dfs_4.withColumn('date_diff', F.datediff(F.to_date(dfs_4.max_time), F.to_date(dfs_4.request_time)))

dfs_5.show()

+--------------------+--------------------+---------+
|        request_time|            max_time|date_diff|
+--------------------+--------------------+---------+
|2017-11-17 00:18:...|2017-11-20 23:59:...|        3|
|2017-11-17 00:07:...|2017-11-20 23:59:...|        3|
|2017-11-17 00:35:...|2017-11-20 23:59:...|        3|
|2017-11-17 00:10:...|2017-11-20 23:59:...|        3|
|2017-11-17 00:03:...|2017-11-20 23:59:...|        3|
|2017-11-17 00:45:...|2017-11-20 23:59:...|        3|
|2017-11-17 00:35:...|2017-11-20 23:59:...|        3|
|2017-11-17 00:59:...|2017-11-20 23:59:...|        3|
|2017-11-17 00:28:...|2017-11-20 23:59:...|        3|
|2017-11-17 00:11:...|2017-11-20 23:59:...|        3|
|2017-11-17 00:13:...|2017-11-20 23:59:...|        3|
|2017-11-17 00:42:...|2017-11-20 23:59:...|        3|
|2017-11-17 00:07:...|2017-11-20 23:59:...|        3|
|2017-11-17 00:40:...|2017-11-20 23:59:...|        3|
|2017-11-17 00:15:...|2017-11-20 23:59:...|        3|
|2017-11-17 00:05:...|2017-11-20 23:59:...|        3|
|2017-11-17 00:50:...|2017-11-20 23:59:...|        3|
|2017-11-17 00:40:...|2017-11-20 23:59:...|        3|
|2017-11-17 00:25:...|2017-11-20 23:59:...|        3|
|2017-11-17 00:35:...|2017-11-20 23:59:...|        3|
+--------------------+--------------------+---------+

我怎么能在几个小时内做同样的事情? 谢谢你的帮助

1 个答案:

答案 0 :(得分:3)

您可以使用hour从日期时间字段中提取小时,然后将其简单地减去新列。现在有一种情况是时差超过一天,你需要在两者之间添加整天。所以我会像你一样创建列天_diff,然后试试这个:

from pyspark.sql import functions as F

dfs_5 = dfs_4.withColumn('hours_diff', (dfs_4.date_diff*24) + 
                          F.hour(dfs_4.max_time) - F.hour(dfs_4.request_time))