Question

我已经在我的main方法中初始化了这个Game（）构造函数，它将2个接口作为参数：

    Game game = new Game(
            (player, bridge) -> {
                if (player instanceof HumanPlayer)
                    return true;
                if (player instanceof RobotPlayer && bridge instanceof FakeBridge)
                    return true;
                return false;
            },
            (player) -> {
                if (player instanceof HumanPlayer) {
                    HumanPlayer hPlayer = (HumanPlayer) player;
                    hPlayer.updateAge(hPlayer.age() + 1);
                    Car car = (Car) hPlayer.vehicle();
                    car.setGas(car.gas());
                } else if (player instanceof RobotPlayer) {
                    RobotPlayer rPlayer = (RobotPlayer) player;
                    rPlayer.updatePower(rPlayer.power() - 5);
                }
                System.out.println(player);
            }
        );

以下是我在Game（）

的构造函数中提供的两个接口

public Initialize initial;
public Interface2 player1;

这是Game类的构造函数：

 public Game(Initialize initial, Interface2 player ) {
     this.initial = initial;
     this.player = player1;
 }

由于某种原因，它仍然给我一个错误： 构造函数游戏（（玩家，桥牌） - ＆gt; {}，（玩家） - ＆gt; {}）未定义

编辑：这是我提供的两个接口：

public interface Initialize {
    boolean constraint(Player player, Bridge bridge);
}

和

public interface Interface2 {
    public boolean constraint2(Player player);
}

Answer 1

您的问题是关于签名与界面不匹配的第二个声明：此编译：

public void run() {
    Game game = new Game((player, bridge) -> {
        return true;
    }, (player) -> {
        return true;
    });
}

public class Bridge {

}

public class Player {

}

public interface Initialize {
    boolean constraint(Player player, Bridge bridge);
}

public interface Interface2 {
    boolean constraint(Player player);
}

public class Game {
    private Initialize initial;
    private Interface2 player;

    public Game(Initialize initial, Interface2 player) {
        this.initial = initial;
        this.player = player;
    }
}

你错过了在你的第二个声明上有一个返回类型

Answer 2

您错过了函数(player) -> {...}的返回语句，但如果您不想返回值，请使用Consumer界面。

尽管如此，我建议您使用interfaces already in place而不是创建自己的完整副本。

如何正确添加接口作为构造函数参数？

2 个答案: