我有这个查询
SELECT BRAND.NAME, FIXTURE.NAME AS FIXTURE_NAME, FIXTURECATEGORY.NAME AS FIXTURE_CATEGORY
FROM V_APPROVED_FIXTURES FIXTURE INNER JOIN
BRAND ON FIXTURE.BRAND_ID = BRAND.ID INNER JOIN
FIXTURECATEGORY ON FIXTURE.FIXTURECATEGORY_ID = FIXTURECATEGORY.ID INNER JOIN
FIXTURE_MODE ON FIXTURE.ID = FIXTURE_MODE.FIXTURE_ID AND FIXTURE.VERSION = FIXTURE_MODE.FIXTURE_VERSION RIGHT JOIN
FIXTURE_MODE_PARAMETER ON FIXTURE_MODE.ID = FIXTURE_MODE_PARAMETER.FIXTURE_MODE_ID AND FIXTURE_MODE.FIXTURE_ID = FIXTURE_MODE_PARAMETER.FIXTURE_ID AND
FIXTURE_MODE.FIXTURE_VERSION = FIXTURE_MODE_PARAMETER.FIXTURE_VERSION
GROUP BY BRAND.NAME, FIXTURE.NAME, FIXTURECATEGORY.NAME
HAVING COUNT(FIXTURE_MODE_PARAMETER.ORDINAL)=25
生成一个唯一结果列表,我想将它与此
结合起来SELECT BRAND.NAME, FIXTURE.NAME AS FIXTURE_NAME, FIXTURECATEGORY.NAME AS FIXTURE_CATEGORY
FROM V_APPROVED_FIXTURES FIXTURE INNER JOIN
BRAND ON FIXTURE.BRAND_ID = BRAND.ID INNER JOIN
FIXTURECATEGORY ON FIXTURE.FIXTURECATEGORY_ID = FIXTURECATEGORY.ID INNER JOIN
FIXTURE_MODE ON FIXTURE.ID = FIXTURE_MODE.FIXTURE_ID AND FIXTURE.VERSION = FIXTURE_MODE.FIXTURE_VERSION RIGHT JOIN
FIXTURE_MODE_PARAMETER ON FIXTURE_MODE.ID = FIXTURE_MODE_PARAMETER.FIXTURE_MODE_ID AND FIXTURE_MODE.FIXTURE_ID = FIXTURE_MODE_PARAMETER.FIXTURE_ID AND
FIXTURE_MODE.FIXTURE_VERSION = FIXTURE_MODE_PARAMETER.FIXTURE_VERSION
GROUP BY BRAND.NAME, FIXTURE.NAME, FIXTURECATEGORY.NAME
HAVING COUNT(FIXTURE_MODE_PARAMETER.ORDINAL)=13
所以,我希望看到所有具有13和25 COUNT(FIXTURE_MODE_PARAMETER.ORDINAL)
我该怎么做?
答案 0 :(得分:2)
由于您的两个查询看起来相同,除了where条件。只需将or
或in
HAVING COUNT(FIXTURE_MODE_PARAMETER.ORDINAL) in(13,25)
答案 1 :(得分:0)
您可以在查询之间放置一个Union语句,如下所示:
Select * from tableA
Union
Select * from tableB
你必须把你的小组放在第二个表之后,如下所示:
Select * from tableA
Union
Select * from tableB
Group by [Column]