Question

我有两个问题。第一个给我一个BusinessUnitIds列表以及每个的计数：

SELECT   [b].[BusinessUnitId], COUNT([b].[BusinessUnitId]) AS bucount
                        FROM     [dbo].[ComponentTeamBusinessUnit] [b]
                        WHERE    [b].[GlobalClientFiscalYearId] = @GlobalClientFiscalYearId
                        AND      [b].[ComponentTeamId] IN (SELECT items FROM [dbo].[fnSplit](@ComponentTeamIds, ','))
                        GROUP BY [b].[BusinessUnitId])

我想在此结果中获取BusinessUnitIds并将它们连接到第二个查询，该查询将检索与BusinessUnitIds关联的业务单位名称。如下所示：

Select [c].Name, [first query result].Count from [dbo].[BusinessUnit] [c]
       INNER JOIN [first query result]
       WHERE [c].BusinessUnitId = [first query result].BusinessUnitId

最终，我想要的是商家名称列表，以及每个商家名称的数量。我一直无法弄清楚如何做到这一点。有人可以帮忙吗？要在一个语句中执行这两个查询都是tops。谢谢。

Answer 1

〔实施例：

SELECT   [b].[BusinessUnitId],A.Name, COUNT([b].[BusinessUnitId]) AS bucount
                        FROM     [dbo].[ComponentTeamBusinessUnit] [b]
                        LEFT JOIN NameTable as A
                        ON A.BusinessUnitId = b.BusinessUnitId 
                        WHERE    [b].[GlobalClientFiscalYearId] = @GlobalClientFiscalYearId
                        AND      [b].[ComponentTeamId] IN (SELECT items FROM [dbo].[fnSplit](@ComponentTeamIds, ','))
                        GROUP BY [b].[BusinessUnitId],A.Name

如果表格是一对一，那将是整洁的，如果一对多，你会看到如下结果：

id name count
1   A     5
1   B     6

如果您想将id 1分组，请获取：

id name count
1   A,B  11

您需要将FOR XML PATH()与STUFF或STRING_SPLIT一起使用，这取决于您的实际情况。

将一个查询的结果与另一个查询联系起来

1 个答案: