我想在一个图中使用多个Hovertool
和Hovertool
的{{1}}属性,以选择性地应用每个工具。举个例子
names
和两个数据来源:
hover1 = HoverTool(tooltips=[("group", "1")], names = ['line1'])
hover2 = HoverTool(tooltips=[("group", "2")], names = ['lines2'])
我想以下(使用bokeh.models API)应该做我想要的事情
source1 = ColumnDataSource(data=dict(
xs=[[1, 3, 2], [3, 4, 6, 6]],
ys=[[2, 1, 4], [4, 7, 8, 5]],
))
source2 = ColumnDataSource(data=dict(
xs=[[1, 3, 2], [6, 7, 9, 8]],
ys=[[-1, 0, 1], [1, 1, 2, 1]]
))
结果图中的p = figure(plot_width=400, plot_height=400)
l1 = MultiLine(xs='xs', ys='ys', name='lines1')
l2 = MultiLine(xs='xs', ys='ys', name='lines2')
p.add_tools(hover)
p.add_tools(hover2)
p.add_glyph(source1, l1)
p.add_glyph(source2, l2)
show(p)
s不起作用(即没有显示工具提示)。使用bokeh.plotting API如下所示,一切都按预期工作:
Hovertool
问题:如何使用bokeh.models API复制bokeh.plotting API的结果?
答案 0 :(得分:2)
Bokeh Documentation中names
模型的HoverTool
属性:
名称:属性类型:List(String)
要查询的名称列表。如果设置,则仅使用具有其name属性匹配值的渲染器。
有了这个
l1 = MultiLine(xs='xs', ys='ys', name='lines1')
您正在为Multiline
对象指定名称,这是一个字形,而不是渲染器。所以试试这个
from bokeh.io import output_notebook, show
output_notebook()
import numpy as np
from bokeh.plotting import figure
from bokeh.models.sources import ColumnDataSource
from bokeh.models.glyphs import MultiLine
from bokeh.layouts import row
from bokeh.models.tools import HoverTool
source = ColumnDataSource(data=dict(
xs1=[[1, 2, 3], [5, 6, 7]],
ys1=[[1, 2, 3], [6, 5, 7]],
xs2=[[7, 8, 9], [1, 2, 3]],
ys2=[[4, 5, 7], [6, 7, 2]],
)
)
hover1 = HoverTool(tooltips=[("group", "1")], names = ['lines1'])
hover2 = HoverTool(tooltips=[("group", "2")], names = ['lines2'])
p = figure(plot_width=400, plot_height=400)
l1 = MultiLine(xs='xs1', ys='ys1')
l2 = MultiLine(xs='xs2', ys='ys2')
r1 = p.add_glyph(source, l1, name='lines1') # the name is assigned to the renderer
r2 = p.add_glyph(source, l2, name='lines2')
# r1.name = 'lines1' # or you could assign the name like this as well
# r2.name = 'lines2'
p.add_tools(hover1)
p.add_tools(hover2)
# p = figure(plot_width=400, plot_height=400, tools=[hover1, hover2])
# p.multi_line(xs='xs1', ys='ys1', source=source, name='lines1')
# p.multi_line(xs='xs2', ys='ys2', source=source, name='lines2')
show(p)