我有一个关于动作的枚举,我想要运行:
public enum theActions
{
action1,
action2
}
我想将它们存储在词典中:
public Dictionary<theActions, Action> _theActions { get; }
_theActions = new Dictionary<theActions, Action>
{
[theActions.action1] = () => action1Func()
};
对于每个动作,我都有自己的功能:
public void action1Func(int inParam)
{
//do whatever
}
稍后,我需要调用其中一个函数:
public void execAction(int inVar, Action action)
{
//inVar isn't the parameter I want to pass to the action. It's used, for something else.
action();
}
execAction(1, _theActions[theActions.action1]);
我不确定,如何更改我的代码以使Action在各处获取参数以及如果我需要一个不需要参数的操作会怎样?我是否必须在该函数中添加虚拟参数?
到目前为止我得到了这个:
using System;
using System.Collections.Generic;
using System.Windows.Forms;
namespace WindowsFormsApp1
{
public partial class Form1 : Form
{
public enum theActions
{
action1,
action2
}
public Dictionary<theActions, Action<int>> _theActions { get; }
public void execAction(int inVar, Action<int> action)
{
//inVar isn't the parameter I want to pass to the action. It's used, for something else.
// action();
}
public Form1()
{
InitializeComponent();
_theActions = new Dictionary<theActions, Action<int>>
{
[theActions.action1] = (Action<int>)((int x) => action1Func(x))
};
}
public void action1Func(int inParam)
{
//do whatever
MessageBox.Show($"Hello ... inParam : {inParam}");
}
private void button1_Click(object sender, EventArgs e)
{
//This works manually
_theActions[theActions.action1].Invoke(12);
//But, I want the execAction to work
//execAction(1, _theActions[theActions.action1]);
}
}
}
它可以手动调用它。我只需要帮助进入execAction()并运行它。所以,关闭。
答案 0 :(得分:0)
尝试删除字典并改为使用它:
public void action1Func(int p1) //action 1 has one int parameter
{
}
public void action2Func() //let's consider action 2 takes no parameters
{
}
public void action3Func(int p1, int p2, int p3)
{
}
// Order of parameters was changed to leverage implicit null parameters for convenience
// See invocations below
public void execAction(theActions action,
int? inVar1 = null, int? inVar2 = null, int? inVar3 = null)
{
switch (action) // Based on action kind, invoke the right function.
{ // The mapping is now coded in a switch statement
// instead of a Dictionary declaration
case theActions.action1: action1Func(inVar1.Value); break;
case theActions.action2: action2Func(); break;
case theActions.action3: action3Func(inVar1.Value, inVar2.Value, inVar3.Value); break;
}
}
// Invocations
execAction(theActions.action1, 1);
execAction(theActions.action2);
execAction(theActions.action3, 1, 3, 5);
如果对execAction正确使用隐式参数声明,则可以使用任意数量的参数调用方法。
您可以执行参数验证(例如,您可以在调用之前检查inVar1.HasValue == true)否则如果省略参数,代码将快速失败(如果HasValue为false,则Nullable.Value抛出InvalidOperationException)。
如果参数数量增加并变得无法管理,您可以将它们放在参数包类中,并通过构造函数验证它们的初始化。
如果定义了这些重载,则可以获得更多安全性(编译时检查):
public void execAction1(int p1)
=> execAction(theActions.action1, p1);
public void execAction2()
=> execAction(theActions.action2);
public void execAction3(int p1, int p2, int p3)
=> execAction(theActions.action3, p1, p2, p3);
// Invocations will be
execAction1(1);
execAction2();
execAction3(1, 3, 5);
但这最后一步打败了目的。您可以改为调用原始方法:)。
答案 1 :(得分:0)
public void execAction(int someInt, Action action)
{
action();
// or: action.Invoke();
}
你应该能够在初始化中删除整个lambda,因为你已经有一个带有一个int参数的方法:
public Form1()
{
InitializeComponent();
_theActions = new Dictionary<theActions, Action<int>>
{
[theActions.action1] = action1Func
};
}
具有特定参数的调用如下所示:
int yourParameter = 12345;
execAction(42, () => (_theActions[theActions.action1]).Invoke(yourParameter));