Question

我正在用Java创建一个文本游戏，它使用2D数组作为电路板。我想这样做，当我输入“扫描”命令时，它每次都会打印相同的8x8板。程序编译得很好我只需要知道如何打印每次运行“scan”命令时生成的相同8x8板。

import java.util.*;
import java.math.*;
import java.util.Random;
import java.util.Scanner;
import java.text.*;
import java.io.*;
public class Main {
    static Scanner in = new Scanner(System.in);
    
        public static void Start() {
        System.out.println("Would you like a Short, Medium, or Long game?");
        String x = in.nextLine();
        System.out.println("Are you a Novice, Fair, Good, Expert, or Emeritus player?");
        String y = in.nextLine();
        System.out.println("Good Luck!");
        System.out.println("What would you like to do?");
        }
        
       public static void main() {
                //create the grid
       String x;
       String y;
       String z;

       z = in.nextLine();
        if (z.equals("scan")) {
        final int rowWidth = 8;
        final int colHeight = 8;
        Random rand = new Random();
        boolean a = true;
        boolean b = true;
        boolean c = true;
        boolean d = true;
        String [][] board = new String[rowWidth][colHeight];
        
        //fill the grid
        for (char row = 0; row < board.length; row++) {
            
            for (char col = 0; col < board[row].length; col++) {
                double r = Math.random();

                
                
                if(a == true && r <= .02) {
                  board[row][col] = "P";
                  a = false; }
                

                 else if(b == true && r <= .04 && r > .02){
                  board[row][col] = "K"; 
                  b = false; }
                

                else if(c == true && r <= .06 && r > .04){
                  board[row][col] = "B";  
                  c = false; }
                  
                 else if(d == true && r <= .08 && r > .06){
                  board[row][col] = " ";  
                  d = false; }
                  
                  
                  else 
                    board[row][col] = "*";
                

                }
            }
       //display output
        for(int i = 0; i < board.length; i++) {

            for(int j = 0; j < board[i].length; j++) {
                    
                System.out.print(board[i][j] + " ");
                //System.out.println();
            }
            System.out.println();
        }
        System.out.println("");
        z = in.nextLine();
        main();
    }else if( z.equals("exit")) {
    System.exit(0);
}else {
           System.out.println("Parton");
            main();
       }   

        }
        
        public static void run() {
            Start();
            main();
        }
        
    }//end of main

//end of class Main

Answer 1

如果这是一个简单的程序，您可以进行简单的更改来执行此操作。只需将数组的范围扩展到类级别，然后创建扫描方法。

public class Main {
    static Scanner in = new Scanner(System.in);
    String[][] board;

    ...//Your other code

    public static scan() {
        //Printing/Drawing logic
    }
}

然后你可以为＆＃34; scan＆＃34;添加一个select语句。到你当前的输入检查，这将运行该方法。

然而，当涉及到这样的设计时，我宁愿有一些由2D数组支持的Board类，它可以包含许多有用的程序函数，包括Board.scan()，以及甚至可能是帮助类来解析输入字符串。

存储2D数组并稍后在Java中再次调用它们

1 个答案: