Question

我有以下输入数据：

type    name    dept    salary
senior  ABC     123     2000
junior  ABC     456     1000
senior  IJK     456     3000
senior  LMN     123     2000
junior  LMN     123     1500
senior  STQ     123     2000

我希望跟随旋转输出：

name    dept    junior_salary   senior_salary
ABC     123     0               2000
ABC     456     1000            0
IJK     456     0               3000
LMN     123     1500            2000
STQ     123     0               2000

以下是我写的LINQ代码：

List<Posting> posting = getData();
posting.GroupBy(x=>new{x.type, x.name, x.dept})
       .Select(x=>new {
             name = x.Key.name,
             dept = x.Key.dept,
             junior_salary = x.Where(z=>x.Key.type=="junior").Sum(y=>y.salary),
             senior_salary = x.Where(z=>x.Key.type=="senior").Sum(y=>y.salary)
         }).ToList();

这给了我不正确的结果。以下是我得到的结果

name    dept    junior_salary   senior_salary
ABC     123     0               2000
ABC     456     1000            0
IJK     456     0               3000
LMN     123     0               2000
LMN     123     1500            0
STQ     123     0               2000

这是我为运行示例创建的小提琴： https://dotnetfiddle.net/QCbyyD

需要帮助。

Answer 1

var pivotList = posting.GroupBy(x=>new{x.name, x.dept})
   .Select(x=>new {
         name = x.Key.name,
         dept = x.Key.dept,
         junior_salary = x.Where(z=>z.type == "junior").Sum(y=>y.salary),
         senior_salary = x.Where(z=>z.type == "senior").Sum(y=>y.salary)
     }).ToList();

修复是从group by子句中删除类型。

Answer 2

这就是你需要的：

var pivotList =
    posting
        .GroupBy(x => new { x.name, x.dept })
        .Select(x => new
        {
            name = x.Key.name,
            dept = x.Key.dept,
            junior_salary = x.Where(z => z.type == "junior").Sum(y => y.salary),
            senior_salary = x.Where(z => z.type == "senior").Sum(y => y.salary)
        })
        .ToList();

您不应该按type分组。

C＃LINQ在桌面上转动

2 个答案: