Question

这是我编写的代码来刮掉＆＃34; blablacar＆＃34;网站。

# -*- coding: utf-8 -*-
import scrapy


class BlablaSpider(scrapy.Spider):
    name = 'blabla'

    allowed_domains = ['blablacar.in']
    start_urls = ['http://www.blablacar.in/ride-sharing/new-delhi/chandigarh']

    def parse(self, response):
        print(response.text)

运行上述内容时，我收到错误

2018-06-11 00:07:05 [scrapy.extensions.telnet] DEBUG：Telnet控制台听取127.0.0.1:6023 2018-06-11 00:07:06 [scrapy.core.engine] DEBUG：Crawled（403）http://www.blablacar.in/robots.txt> （引用者：无）2018-06-11 00:07:06 [scrapy.core.engine] DEBUG：抓取（403）http://www.blablacar.in/ride-sharing/new-delhi/chandigarh> （引荐：无）2018-06-11 00:07:06 [scrapy.spidermiddlewares.httperror]信息：忽略响应＆lt; 403 http://www.blablacar.in/ride-sharing/new-delhi/chandigarh＆gt;：HTTP 状态代码未处理或不允许2018-06-11 00:07:06 [scrapy.core.engine]信息：关闭蜘蛛（已完成）

Answer 1

通常在html中，403错误表示您无权访问该页面。

如果没有显示相同的错误，请尝试使用其他网站，这可能是因为网站回复引起的

Answer 2

您需要配置用户代理。我使用配置的用户代理在我的站点中运行您的代码，并且我获得了状态代码200。

1置于具有名称utils.py

的settings.py新文件附近

import random

user_agent_list = [
    # Chrome
    'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/60.0.3112.113 Safari/537.36',
    'Mozilla/5.0 (Windows NT 6.1; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/60.0.3112.90 Safari/537.36',
    'Mozilla/5.0 (Windows NT 5.1; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/60.0.3112.90 Safari/537.36',
    'Mozilla/5.0 (Windows NT 6.2; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/60.0.3112.90 Safari/537.36',
    'Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/44.0.2403.157 Safari/537.36',
    'Mozilla/5.0 (Windows NT 6.3; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/60.0.3112.113 Safari/537.36',
    'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/57.0.2987.133 Safari/537.36',
    'Mozilla/5.0 (Windows NT 6.1; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/57.0.2987.133 Safari/537.36',
    'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/55.0.2883.87 Safari/537.36',
    'Mozilla/5.0 (Windows NT 6.1; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/55.0.2883.87 Safari/537.36',
    'Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/53.0.2785.116 Safari/537.36'
    # Firefox
    'Mozilla/4.0 (compatible; MSIE 9.0; Windows NT 6.1)',
    'Mozilla/5.0 (Windows NT 6.1; WOW64; Trident/7.0; rv:11.0) like Gecko',
    'Mozilla/5.0 (compatible; MSIE 9.0; Windows NT 6.1; WOW64; Trident/5.0)',
    'Mozilla/5.0 (Windows NT 6.1; Trident/7.0; rv:11.0) like Gecko',
    'Mozilla/5.0 (Windows NT 6.2; WOW64; Trident/7.0; rv:11.0) like Gecko',
    'Mozilla/5.0 (Windows NT 10.0; WOW64; Trident/7.0; rv:11.0) like Gecko',
    'Mozilla/5.0 (compatible; MSIE 9.0; Windows NT 6.0; Trident/5.0)',
    'Mozilla/5.0 (Windows NT 6.3; WOW64; Trident/7.0; rv:11.0) like Gecko',
    'Mozilla/5.0 (compatible; MSIE 9.0; Windows NT 6.1; Trident/5.0)',
    'Mozilla/5.0 (Windows NT 6.1; Win64; x64; Trident/7.0; rv:11.0) like Gecko',
    'Mozilla/5.0 (compatible; MSIE 10.0; Windows NT 6.1; WOW64; Trident/6.0)',
    'Mozilla/5.0 (compatible; MSIE 10.0; Windows NT 6.1; Trident/6.0)',
    'Mozilla/4.0 (compatible; MSIE 8.0; Windows NT 5.1; Trident/4.0; .NET CLR 2.0.50727; .NET CLR 3.0.4506.2152; .NET CLR 3.5.30729)',
    'Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:59.0) Gecko/20100101 Firefox/59.0'
]


def get_random_agent():
    return random.choice(user_agent_list)

2添加到您的settings.py文件：

from <SCRAPY_PROJECT>.utils import get_random_agent

USER_AGENT = get_random_agent()

Answer 3

According to Scrapy documentation，您可以使用handle_httpstatus_list蜘蛛属性。

以您为例：

class BlablaSpider(scrapy.Spider):
    name = 'blabla'

    allowed_domains = ['blablacar.in']
    start_urls = ['http://www.blablacar.in/ride-sharing/new-delhi/chandigarh']
    handle_httpstatus_list = [403]

爬行时scrapy中的错误403

3 个答案: