here my dataset
df=structure(list(id = c(1030879980L, 1030879990L), jan = c(170L,
265L), feb = c(153L, 332L), march = c(170L, 290L), apr = c(1L,
425L), may = c(66L, 406L), jume = c(125L, 352L), jul = c(129L,
339L), aug = c(-109L, 470L), sept = c(56L, 486L), oct = c(37L,
440L), nov = c(52L, 589L), dec = c(63L, 659L)), .Names = c("id",
"jan", "feb", "march", "apr", "may", "jume", "jul", "aug", "sept",
"oct", "nov", "dec"), class = "data.frame", row.names = c(NA,
-2L))
如何将其垂直移调以进行时间序列分析。 有很多障碍。我无法手动完成。 在我预期的输出
id month value
1030879980 jan 507
1030879981 feb 502
1030879982 march 431
1030879983 apr 429
1030879984 may 449
1030879985 jume 368
1030879986 jul 406
1030879987 aug 290
1030879988 sept 309
1030879989 oct 371
1030879990 nov 481
1030879991 dec 536
1030879990 jan 265
1030879991 feb 332
1030879992 march 290
1030879993 apr 425
1030879994 may 406
1030879995 jume 352
1030879996 jul 339
1030879997 aug 470
1030879998 sept 486
1030879999 oct 440
1030880000 nov 589
1030880001 dec 659
如何执行?
答案 0 :(得分:1)
您可以使用melt
或data.table
个套件中的reshape2
功能:
library(data.table)
dt <- data.table(df)
dt.ts <- melt(dt, id.vars = "id", value.name = "value")