Question

这是html ...

<form name="stream" method="post" action="scripts/validate.php">
  <div class="form-check">
    <input class="form-check-input" type="checkbox" name="attend" value="yes" autocomplete="off">
    <label class="form-check-label" for="attend">Yes, I will attend the event in Edo State.</label>
  </div>
  <div class="form-check">
    <input class="form-check-input" type="checkbox" name="trad" value="yes" autocomplete="off">
    <label class="form-check-label" for="trad">Yes, I'm interested in getting the Asoebi.</label>
  </div>
  <div class="form-check">
    <input class="form-check-input" type="checkbox" name="house" value="yes" autocomplete="off">
    <label class="form-check-label" for="house">Yes, I am interested in getting Accommodation.</label>
  </div>

  <button class="btn bg-bur text-white h4 btn-block mt-20" type="submit" name="stream">Submit</button>
</form>

这里是处理表单数据的php，但它仍然显示相同的结果，“即使选中1复选框或未选中任何复选框，我仍希望完整注册”

<?php 
if( isset( $_POST['stream'] ) ) {    
    if ($_POST['attend'] == 'yes' && $_POST['trad'] == 'yes' && $_POST['house'] == 'yes' ) {
        echo "I want the full registration";
    }
    elseif ($_POST['attend'] == 'yes' && $_POST['trad'] == 'yes' && $_POST['house'] !== 'yes' ) {
        echo "I want the Asoebi and I will attend";
    }
    elseif ($_POST['attend'] == 'yes' && $_POST['trad'] !== 'yes' && $_POST['house'] !== 'yes' ) {
        echo "I am only attending";
    }
    elseif ($_POST['attend'] !== 'yes' && $_POST['trad'] == 'yes' && $_POST['house'] !== 'yes' ) {
        echo "I only want Asoebi";
    }
    elseif ($_POST['attend'] !== 'yes' && $_POST['trad'] !== 'yes' && $_POST['house'] !== 'yes' ) {
        echo "You haven't selected anything";
    }
}
?>

Answer 1

勾选此框时，$ _POST [name-not-id]返回值。有点烦人（对我来说），未选中的复选框根本不会返回任何内容。所以，以参加为例：

<input class="form-check-input" type="checkbox" name="attend" value="yes">

当选中此框时，

将在$ _POST [“参加”]中返回“是”，当取消选中该框时，$ _POST中没有值。因此，您可以使用多个测试来查看是否已选中。例如：

if (!empty($_POST["attend"])) ...

或

if (isset($_POST["attend"]) && $_POST["attend"] === "yes") ...

Answer 2

最后让它发挥作用。

<?php error_reporting(0); if( isset( $_POST['stream'] ) ) {    
if ($_POST['attend'] == 'yes' && $_POST['trad'] == 'yes' && $_POST['house'] == 'yes' ) {
    echo "I want the full registration";
}
elseif ($_POST['attend'] == 'yes' && $_POST['trad'] == 'yes' && $_POST['house'] !== 'yes' ) {
    echo "I want the Asoebi and I will attend";
}
elseif ($_POST['attend'] == 'yes' && $_POST['trad'] !== 'yes' && $_POST['house'] !== 'yes' ) {
    echo "I am only attending";
}
elseif ($_POST['attend'] !== 'yes' && $_POST['trad'] == 'yes' && $_POST['house'] !== 'yes' ) {
    echo "I only want Asoebi";
}
elseif ($_POST['attend'] !== 'yes' && $_POST['trad'] !== 'yes' && $_POST['house'] !== 'yes' ) {
    echo "You haven't selected anything";
} }?>

我想对从php中的表单发布的值执行逻辑运算

2 个答案: