Question

我在 php

中设置了一些数组

$usersPostsDates = array();
$usersPostsNations = array();
$userpostsIds = array();

if (!in_array($jikuDate, $usersPostsDates)) {
    array_push($usersPostsDates, $jikuDate);
}
if (!in_array($nation, $usersPostsNations)) {
    array_push($usersPostsNations, $nation);
}
if (!in_array($idThisPost, $userpostsIds)) {
    array_push($userpostsIds, $idThisPost);
}

然后在 js 我做：

var userDates = <?php echo json_encode($usersPostsDates); ?>;
var userNations = <?php echo json_encode($usersPostsNations); ?>;
var userIds = <?php echo json_encode($userpostsIds); ?>;
var i;
var a;
var b;
for (i = 0; i < userDates.length; ++i) {
  $("#usp-custom-i"+i).attr("value", userDates[i]);
}
for (a = 0; a < userNations.length; ++a) {
  $("#usp-custom-a"+a).attr("value", userNations[a]);
}
for (b = 0; b < userIds.length; ++b) {
  $("#usp-custom-b"+b).attr("value", userIds[b]);
}

但是控制台给了我：

var userDates = ["1859","1858","1857"];
var userNations = ["United States"];
var userIds = [15221,3260,969];

为什么var userIds = [15221,3260,969]; isn't var userIds = ["15221","3260","969"];？

如果我这样做：var_dump($userpostsIds);我得到array(1) { [0]=> int(15221) } array(2) { [0]=> int(15221) [1]=> int(3260) } array(3) { [0]=> int(15221) [1]=> int(3260) [2]=> int(969) }

Answer 1

因为如果您希望int(15221)将数据转换为字符串，那么您的数据就像""中所见的那样。

尝试以下操作：

array_push($userpostsIds, $idThisPost.'');

数组推送值不是字符串

1 个答案: