Question

只是想知道是否有办法将数组中的所有内容推送到一个。例如：

//This will add the first error to array
$error[] = "You must provide a first_name";

//This will add the second error to array
$error[] = "You must provide a last_name";

//This error i want to add at the first index of the array, while pushing the previous two that are already added down a value. But doing it the way i've been doing it just replaces the first index
$error[0] = "This will push the other two errors down one index";

无论如何都没有实际删除数组索引中的第一个值。

固定版本：

//This will add the first error to array
$error[] = "You must provide a first_name";

//This will add the second error to array
$error[] = "You must provide a last_name";

//This error i want to add at the first index of the array, while pushing the previous two that are already added down a value. But doing it the way i've been doing it just replaces the first index
array_unshift($error, "This will push the other two errors down one index");

感谢Sharanya Dutta。

Answer 1

内置的PHP函数array_unshift将满足您的目的：

$error = array();
$error[] = "You must provide a first_name";
$error[] = "You must provide a last_name";
array_unshift($error, "This will push the other two errors down one index");
print_r($error);

输出将是：

Array
(
    [0] => This will push the other two errors down one index
    [1] => You must provide a first_name
    [2] => You must provide a last_name
)

DEMO

Answer 2

疯狂的黑客入侵从大价值开始添加。：^）

$error[1000] = "You must provide a first_name";
$error[] = "You must provide a last_name";
$error[0] = "This will push the other two errors down one index";

将数组值推1

2 个答案: