如何将多个月的数据转换为多个列

Question

我有一个示例查询，如下所示，

SELECT SUM(Test) AS TotalLastMonth
FROM Table
WHERE  date >=DATEADD(MONTH, -1, getdate())
GROUP BY InvoiceNo

结果：

    22
    12
    34
    21
    16
    10
    18

我正在尝试将多个月的数据检索到多个列中。示例输出

TotalLastMonth TotalLast6Months TotalLast12Months
10              22                   97
12              24                   57
15              30                   63
21              42                   78
25              50                   75

Answer 1

条件聚合可行......

select 
     TotalLastMonth = sum(case when date >= dateadd(month,-1,getdate()) then Test end)
    ,TotalLast6Months = sum(case when date >= dateadd(month,-6,getdate()) then Test end)
    ,TotalLast6Months = sum(case when date >= dateadd(month,-12,getdate()) then Test end)

如果您想要在本月之外的整月，请使用您的DATEADD逻辑来获取本月的第一个月以及该月的最后一个月。

select
     --total last month, not including this month 
     TotalLastMonth = sum(case when date >= DATEADD(MONTH, DATEDIFF(MONTH, 0, GETDATE())-1, 0) and date < DATEADD(MONTH, DATEDIFF(MONTH, 0, GETDATE()), 0) then Test end)
     --total last 6 months not including this month
    ,TotalLast6Months = sum(case when date >= DATEADD(MONTH, DATEDIFF(MONTH, 0, GETDATE())-6, 0) and date <  DATEADD(MONTH, DATEDIFF(MONTH, 0, GETDATE()), 0) then Test end)
     --total last 12 months not including this month
    ,TotalLast6Months = sum(case when date >= DATEADD(MONTH, DATEDIFF(MONTH, 0, GETDATE())-12, 0) and date <  DATEADD(MONTH, DATEDIFF(MONTH, 0, GETDATE()), 0) then Test end)