Question

我想提取元素geo:lat，但我不知道如何

我这样做但是没有用：

PREFIX fun: <http://w3id.org/sparql-generate/fn/>
PREFIX iter: <http://w3id.org/sparql-generate/iter/>
PREFIX geo: <http://www.opengis.net/ont/geosparql#>
PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
PREFIX xsd: <http://www.w3.org/2001/XMLSchema#>
PREFIX xmlns: <http://www.georss.org/georss>


GENERATE {
   ?id a  geo:SpatialThing;
       rdfs:label  ?name;
       geo:lat  "{?lat}"^^xsd:decimal;
       geo:long "{?long}"^^xsd:decimal .
}

SOURCE <http://wcf.tourinsoft.com/Syndication/cdt37/A716E167-B408-45AA-BEAB-01E466942A8C/Objects> AS ?source
ITERATOR iter:XPath(?source,"/feed/entry") AS ?it
WHERE {
  BIND(fun:XPath(?it,"/entry/id/text()") AS ?id)
  BIND(fun:XPath(?it,"/entry/title/text()") AS ?name)
  BIND(fun:XPath(?it,"/entry/lat/text()") AS ?lat)
  BIND(fun:XPath(?it,"/entry/geo:long/text()") AS ?long)    
}

我需要在feed/entry/geo:long中获取信息，我的问题是此元素geo:long的名称。

我有一个感兴趣的列表，我正在尝试获取这些POI的名称和经度和经度 https://ci.mines-stetienne.fr/sparql-generate/playground.html

sparql xml如何提取这个元素？

0 个答案: