我有以下多维数组。我没有得到适合我的问题的标题。您可以自由编辑和更改。
Array(
[2018-05-01] => Array
(
[0] => Array
(
[Zone] => 0
[Time] => 13:06
)
[1] => Array
(
[Zone] => 0
[Time] => 13:08
)
[2] => Array
(
[Zone] => 2
[Time] => 13:10
)
[3] => Array
(
[Zone] => 2
[Time] => 13:14
)
[4] => Array
(
[Zone] => 0
[Time] => 13:16
)
[5] => Array
(
[Zone] => 0
[Time] => 13:17
)
[6] => Array
(
[Zone] => 2
[Time] => 13:21
)
[7] => Array
(
[Zone] => 2
[Time] => 13:25
)
[8] => Array
(
[Zone] => 0
[Time] => 13:28
)
[9] => Array
(
[Zone] => 0
[Time] => 13:32
)
)
[2018-05-04] => Array
(
[0] => Array
(
[Zone] => 1
[Time] => 13:26
)
[1] => Array
(
[Zone] => 1
[Time] => 13:28
)
[2] => Array
(
[Zone] => 1
[Time] => 13:30
)
[3] => Array
(
[Zone] => 0
[Time] => 13:34
)
[4] => Array
(
[Zone] => 0
[Time] => 13:36
)
[5] => Array
(
[Zone] => 1
[Time] => 13:37
)
[6] => Array
(
[Zone] => 1
[Time] => 13:41
)
)
)
我必须以这样一种方式操纵上面的数组，即同一区域不应该同时出现。这取决于条件 -
条件1
如果子数组只有Zone => 0 and Zone => 2。例如，带有键2018-05-01的数组只有0和2作为区域。
我们只会获取First Zone =＆gt; 0，最后一个Zone =＆gt; 2，第一区=＆gt; 0并且最后一次Zone =＆gt; 2.
请注意，如果没有Zone =＆gt; Zone =＆gt;之后的2 0，然后在这种情况下我们获取最后的Zone =＆gt; 0而不是第一个Zone =＆gt; 0。 请查看我的输出以获得清除。
条件2
如果子数组有Zone => 1。例如，键为2018-05-04的数组。我们只会获取每个的第一次出现。
这是所需的输出
Array(
[2018-05-01] => Array
(
[0] => Array
(
[Zone] => 0
[Time] => 13:06
)
[3] => Array
(
[Zone] => 2
[Time] => 13:14
)
[4] => Array
(
[Zone] => 0
[Time] => 13:16
)
[7] => Array
(
[Zone] => 2
[Time] => 13:25
)
[9] => Array
(
[Zone] => 0
[Time] => 13:32
)
)
[2018-05-04] => Array
(
[0] => Array
(
[Zone] => 1
[Time] => 13:26
)
[3] => Array
(
[Zone] => 0
[Time] => 13:34
)
[5] => Array
(
[Zone] => 1
[Time] => 13:37
)
)
)
我尝试的是 -
我一直在考虑的是使用array_column来检查子数组是否有“1”作为Zone值。如果是，那么我们将实现条件1，否则条件2.然后遍历每个子阵列并将当前迭代与前一个迭代进行比较。但我没有得到确切的观点，我怀疑这是否是一个优雅的解决方案。