我们如何找到multidimensional array
中重复元素的数量,
我有一个像这样的数组:
Array
(
[0] => Array
(
[brti] => 29
)
[1] => Array
(
[voda] => 6
)
[2] => Array
(
[btel] => 8
)
[3] => Array
(
[btel] => 10
)
)
问题:如何简化数组的结构,我的意思是如果有指示具有相同的键,则可以对值进行计数?
就是这样:
Array
(
[0] => Array
(
[brti] => 29
)
[1] => Array
(
[voda] => 6
)
[2] => Array
(
[btel] => 18
)
)
到目前为止,我已经尝试过这种方法,但是对我没有帮助。 My array is store in $test
$test = [sample array]
$count = array();
foreach ($test as $key => $value) {
foreach ($value as $k => $val) {
if (isset($count[$val])) {
++$count[$val];
} else {
$count[$value] = 1;
}
}
}
print_r($count);
答案 0 :(得分:1)
<?php
$array = [
"0" => ["brti" => 29],
"1" => ["voda" => 6],
"2" => ["btel" => 8],
"3" => ["btel" => 10],
];
$final = array();
array_walk_recursive($array, function($item, $key) use (&$final){
$final[$key] = isset($final[$key]) ? $item + $final[$key] : $item;
});
print_r($final);
});
答案 1 :(得分:0)
您可以通过非常简单的方式来完成
$test = [];
foreach ($array as $value)
{
foreach ($value as $k => $v)
{
// $test[$k] = ($test[$k] ?? 0); // initialised if not php 7+
$test[$k] = (empty($test[$k]) ? 0: $test[$k]); // below php 7
$test[$k] += $v;
}
}
print_r($test);
输出:
Array
(
[brti] => 29
[voda] => 6
[btel] => 18
)
工作demo。