Question

我想问一下，我可以将多个IN运算符与AND查询结合起来吗？我的代码需要你的帮助。这是我尝试但不能正常工作的代码。

if ($areas != '' || $city_check != '' || $course != '' || $subject_check != '') {
        $countcity = count($city_check);
        $countsubject = count($subject_check);

        $area_ids = implode(',',$city_check);
        $subject_ids = implode(',',$subject_check);

        $sql .= "AND TAC.tac_st_id = '".$areas."' AND TAC.tac_city_id IN($area_ids) 
                AND TRS.trs_tc_id = '".$course."' AND TRS.trs_ts_id IN($subject_ids)
                GROUP BY U.u_username
                HAVING COUNT(distinct TAC.tac_city_id) = '".$countcity."' COUNT(distinct TRS.trs_ts_id) = '".$countsubject."'
                ";
    }

没有结果。

我已经完成了下面的代码，它按照我想要的方式工作，但它只能运行if中的每个块。如果我想搜索city_check，则subject_check将无效，反之亦然。

//search for cities
// if ($areas != '' || $city_check != '') {

    //     $countcity = count($city_check);

    //     $sql .= "AND TAC.tac_st_id = '".$areas."' AND TAC.tac_city_id IN(".implode(',',$city_check).")
    //             GROUP BY U.u_username
    //             HAVING COUNT(distinct TAC.tac_city_id) = '".$countcity."'
    //             ";
    // }

//search for subject
    // if ($course != '' || $subject_check != '') {

    //     $countsubject = count($subject_check);
    //     // echo json_encode(["message"=>$countcity]);

    //     $sql .= "AND TRS.trs_tc_id = '".$course."' AND TRS.trs_ts_id IN(".implode(',',$subject_check).")
    //             GROUP BY U.u_username
    //             HAVING COUNT(distinct TRS.trs_ts_id) = '".$countsubject."'
    //             ";

    //         }

我想要的是，城市和主题都可以一起搜索。谢谢你们提前帮助。

编辑：我尝试在phpmyadmin中输出我的SQL

SELECT U.u_username,U.u_email,U.u_status,ST.st_name,CT.city_name,TC.tc_title,TS.ts_title
FROM tk_user as U
INNER JOIN tk_user_details    AS UD  ON UD.ud_u_id   = U.u_id

LEFT JOIN tk_tutor_subject AS TRS ON TRS.trs_u_id = U.u_id 
LEFT JOIN tk_tution_course   AS TC  ON TC.tc_id     = TRS.trs_tc_id  
LEFT JOIN tk_tution_subject   AS TS  ON TS.ts_id     = TRS.trs_ts_id
LEFT JOIN tk_tutor_area_cover AS TAC ON TAC.tac_u_id = U.u_id 
LEFT JOIN tk_cities CT ON CT.city_id   = UD.ud_city AND TAC.tac_city_id = CT.city_id  
LEFT JOIN tk_states AS ST ON TAC.tac_st_id = ST.st_id
LEFT JOIN tk_countries AS C ON ST.st_c_id = C.c_id AND CT.city_c_id = C.c_id

WHERE U.u_status <> 'D'
AND TAC.tac_st_id = 1046 AND TAC.tac_city_id IN(16,17)
AND TRS.trs_tc_id = 5 AND TRS.trs_ts_id IN(8,9)

GROUP BY U.u_username
HAVING COUNT(distinct TAC.tac_city_id) = 2 AND COUNT(distinct TRS.trs_ts_id) = 2

Answer 1

如果其中一个可能是空的，你应该使用类似的东西：

使用OR

...
WHERE U.u_status <> 'D' 
    AND 
    (
        (TAC.tac_st_id = 1046 AND TAC.tac_city_id IN(16,17) )
        OR 
        (TRS.trs_tc_id = 5 AND TRS.trs_ts_id IN(8,9) )
    )
...

多个IN运算符mysql结合在一起

1 个答案: