我有三张桌子;
用户表
id first_name last_name country
2 John Doe USA
3 Jimmy Biglips FRA
user_meta (元数据)表
user_id meta_key meta_value
2 phone 3333
2 rating Good
3 phone 7777
3 rating Bad
国家/地区表
country_id country country_fullname
1 USA United States of America
2 FRA France
我需要按“评分”进行查询(例如“良好”)并将结果集返回为;
id first_name last_name phone rating country country_fullname
2 John Doe 33333 Good USA United States of America
由于 user_meta 表有多行与用户表中的成员对应,因此我无法在一行中返回一组合并的值。
谢谢。
答案 0 :(得分:2)
尝试
SELECT u.id,
u.first_name,
u.last_name,
MIN(CASE WHEN meta_key = 'phone' THEN meta_value END) phone,
MIN(CASE WHEN meta_key = 'rating' THEN meta_value END) rating,
u.country,
c.country_fullname
FROM user u LEFT JOIN user_meta m
ON u.id = m.user_id LEFT JOIN country c
ON u.country = c.country
GROUP BY u.id
输出:
| ID | FIRST_NAME | LAST_NAME | PHONE | RATING | COUNTRY | COUNTRY_FULLNAME | ------------------------------------------------------------------------------------- | 2 | John | Doe | 3333 | Good | USA | United States of America | | 3 | Jimmy | Biglips | 7777 | Bad | FRA | France |
这是 SQLFiddle 演示
答案 1 :(得分:2)
您只需将它们合并到JOIN
即可。即使用户没有可用的电话/评级,LEFT JOIN
也可以显示该行;
SELECT u.id, u.first_name, u.last_name, p.meta_value phone, r.meta_value rating,
u.country, c.country_fullname
FROM user u
LEFT JOIN user_meta p ON u.id=p.user_id AND p.meta_key='phone'
LEFT JOIN user_meta r ON u.id=r.user_id AND r.meta_key='rating'
JOIN country c ON u.country=c.country;