Question

我需要在文件夹中运行python脚本。
脚本计数文件（图像）编号为其创建图像每64张图片。例如：如果包含640个图像的文件夹，我将获得10个图像为64张图像/ outputimage的组合

只是，在添加“for”指令之前，我可以得到一个结果，但是手动并且只能使用相同的图像（图像重复）。

任何想法？

所以我按照以下步骤进行：

import os
import os.path

from PIL import Image

list = os.listdir(".")  # current directory 
number_files = len(list)
print (number_files)

for x in range(0, number_files):

    # files = ['x.png']  

        # opens an image: here I can't find how 
    im = Image.open("1.png") # here I tried to 

# creates a new empty image, RGB mode, and size 800 by 800.
new_im = Image.new('RGB', (800, 800))

# Here I resize my opened image, so it is no bigger than 100,100
im.thumbnail((100, 100))
# Iterate through a 8 by 8 grid with 100 spacing, to place my image
for i in xrange(0, 800, 100):
    for j in xrange(0, 800, 100):
        # paste the image at location i,j:
        new_im.paste(im, (i, j))
        new_im.save(os.path.expanduser('outputimage.png'))

更新：

import os
import os.path

from PIL import Image


def drange(start, stop, step):
    while start < stop:
        yield start
        start += step


list = os.listdir(".")  # directory path
number_files = len(list)
print (number_files)

new_im = Image.new('RGB', (800, 800))

for x in drange(0, number_files, 64):

    im = Image.open(list[x])
    im.thumbnail((100, 100))

    for i in xrange(0, 800, 100):
        for j in xrange(0, 800, 100):

            new_im.paste(im, (i, j))

new_im.save(os.path.expanduser('out.png'))

基于Sven解决方案的其他更新：

import os.path

from PIL import Image

fileList = [] where_to_look = "png/" 
  for f in os.listdir(where_to_look):
        if os.path.isfile(os.path.join(where_to_look, f)):
            fileList.append(f)
             print (len(fileList))


target_img = None n_targets = 0 collage_saved = False

for n in range(len(fileList)):
    img = Image.open(fileList[n])
    img.thumbnail((100, 100))

    if n % 64 == 0:
        # create an empty image for a collage
        target_img = Image.new("RGB", (800, 800))
        n_targets += 1
        collage_saved = False

    # paste the image at the correct position
    i = int(n / 8)
    j = n % 8
    target_img.paste(img, (100*i, 100*j))

    if (n + 1) % 64 == 0 and target_img is not None:
        # save a finished 8x8 collage
        target_img.save("{0:04}.png".format(n_targets))
        collage_saved = True

# save the last collage if not collage_saved:
    target_img.save("{0:04}.png".format(n_targets))

Answer 1

根据您的更新，我快速勾勒出了一个解决方案。请注意我没有测试它：

import os
from PIL import Image

image_dir = os.path.abspath("png")
# list all files in directory
files = os.listdir(image_dir)
# get all PNGs
png_files = filter(lambda x: x.endswith(".png"), files)
# make file paths absolute
image_files = map(lambda x: os.sep.join([image_dir, x]), png_files)

n_files = len(image_files)

target_img = None
n_targets = 0
collage_saved = False
for n in range(n_files):
    img = Image.open(image_files[n])
    img.thumbnail((100, 100))

    if n % 64 == 0:
        # create an empty image for a collage
        target_img = Image.new("RGB", (800, 800))
        n_targets += 1
        collage_saved = False

    # paste the image at the correct position
    i = int(n / 8)
    j = n % 8
    target_img.paste(img, (100*i, 100*j))

    if (n + 1) % 64 == 0 and target_img is not None:
        # save a finished 8x8 collage
        target_img.save("{0:04}.png".format(n_targets))
        collage_saved = True

# save the last collage
if not collage_saved:
    target_img.save("{0:04}.png".format(n_targets))

这将遍历所有图像并将它们组装成8x8网格（我在脚本中将其称为拼贴）。每当网格填满时，拼贴就会保存为文件，其命名模式为0001.png，0002.png，等等。

请注意，有一些要改进的地方：

os.listdir(".")将为您提供目录中的所有文件，而不仅仅是图片。您必须过滤图像文件的输出。
这仅适用于当前工作目录。
输出也会保存到当前工作目录。

更新：过滤PNG并使用绝对路径

使用Pillow和Python组合文件

1 个答案: