Question

我只是不想这样做：

findAllByEntityAnd*(Long entityId, *)

相反，我想做：

java.lang.IllegalArgumentException: Could not create query metamodel for method public abstract java.util.List com.worksap.morphling.raptor.dump.thread.dao.ThreadDoRepository.findAllByDumpDoAndLocksWaitingContains(java.lang.Long,java.lang.String)!

是否有一些我错过了实现我想要的东西，或者我无法直接实现它？

感谢您的帮助〜

当我尝试时，春天促使我：

@Data
@Builder
@Entity
@Table(name = "thread_info")
@AllArgsConstructor
@NoArgsConstructor
public class ThreadDo implements Serializable {
    private static final long serialVersionUID = -1L;
    String name;
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Long id;
    @ManyToOne
    @JoinColumn(name = "thread_dump_id")
    @JsonIgnore
    private ThreadDumpDo dumpDo;

    ...
}

@Data
@Builder
@Entity
@Table(name = "thread_dump")
@AllArgsConstructor
@NoArgsConstructor
public class ThreadDumpDo implements Serializable {
    private static final long serialVersionUID = -1L;

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Long id;

    @OneToMany(
            mappedBy = "dumpDo",
            cascade = CascadeType.ALL,
            orphanRemoval = true
    )
    private List<ThreadDo> threadDoList;
}

这是我的表格供您参考：

ThreadDoRepository

然后我有一个threadDos并希望直接找到List<ThreadDo> findAllByDumpDoAndLocksWaitingContains(Long dumpId, String lockWaiting);：

@Query

我可以通过@Query(value = "select * from thread_info t where t.thread_dump_id = ?1 and t.locks_waiting like ?2", nativeQuery = true) List<ThreadDo> findAllByDumpDoAndLocksWaitingContains(Long dumpId, String lockWaiting);实现如下，但我认为这很难看，因为它很容易解释（我认为）。

{{1}}

Answer 1

试试这个

List<ThreadDo> findAllByDumpDo_IdAndLocksWaitingContains(Long dumpId, String lockWaiting);

Jpa findAllBy *使用Long id而不是实体

1 个答案: