如何做非专业类型有接受Function1的方法?

时间:2018-06-03 14:07:13

标签: scala function testing mockito

我有以下课程:

class Elem[T](t: T){
  def doSome(f: T => Unit):Unit = f(t)
}

所以我想测试给定Elem实例的函数调用(我在做mockito)。运行测试时

val f = mock(classOf[Int => Unit])
new Elem(1).doSome(f)
verify(f).apply(1)

我遇到以下异常:

Wanted but not invoked:
function1.apply$mcVI$sp(1);

However, there was exactly 1 interaction with this mock:
function1.apply(1);

这是合理的,因为Function1专门用于Int。所以进行测试

val f = mock(classOf[AnyRef => Unit])
new Elem(1.asInstanceOf[AnyRef]).doSome(f)
verify(f).apply(1.asInstanceOf[AnyRef])

工作正常。

有没有办法避免这种丑陋的演员阵容AnyRef?也许有另一种工具比mockito更适合这种情况?

2 个答案:

答案 0 :(得分:4)

这是强制编译器使用非专用泛型apply

的一种方法
  def verifyGenericApply[X, Y](f: X => Y, x: X): Unit = {
    verify(f).apply(x)
  }

  "Int function" should "invoke non-specialized apply" in {
    class Elem[T](t: T){
      def doSome(f: T => Unit):Unit = f(t)
    }
    val f = mock(classOf[Int => Unit])
    new Elem(1).doSome(f)
    verifyGenericApply(f, 1)
  }

我对mockito不够熟悉,不能保证这是惯用的,但是......

答案 1 :(得分:2)

ScalaMock似乎开箱即用:

import org.scalatest._
import org.scalatest.matchers._
import org.scalamock.scalatest.MockFactory
import org.scalamock.scalatest._

class Elem[T](t: T){
  def doSome(f: T => Unit):Unit = f(t)
}

class ExampleSpec extends FlatSpec with Matchers with MockFactory {

  "Elem.doSome" should "apply given function once" in {
    val f = mockFunction[Int, Unit]
    f.expects(1).returning({}).once
    new Elem(1).doSome(f)
  }
}

run(new ExampleSpec)