Question

我有一个方法serializetoxml，它接受obj1类型的对象作为其参数：

class Program
{
    static void Main(string[] args)
    {
        obj1 myobj = new obj1();
        serializetoxml(myobj);    
    }
}

public class obj1
{
    public string a { get; set; }
    public int b { get; set; }
    public bool c { get; set; }
}

public static void serializetoxml(obj1 myobj)
{
    XmlSerializer myserializer = new XmlSerializer(typeof(obj1));
    TextWriter mywriter = new StreamWriter("C:\\my.xml");
    myserializer.Serialize(mywriter, myobj);
    mywriter.Close();
}

现在我有一个类obj2，我希望将其作为参数传递

public class obj2
{
    public int a { get; set; }
    public bool b { get; set; }
    public List<string> c { get; set; }
}

如何重用serializetoxml方法以便能够接受其他类型的参数，这样我就不会再次编写相同的方法并将typeof更改为obj2？

obj2 myobj = new obj2();
serializetoxml(myobj);

Answer 1

添加类型参数：

public static void serializetoxml<T>(T myobj)
{
    XmlSerializer myserializer = new XmlSerializer(typeof(T));
    TextWriter mywriter = new StreamWriter("C:\\my.xml");
    myserializer.Serialize(mywriter, myobj);
    mywriter.Close();
}

然后你会像：

一样使用它

serializetoxml<obj2>(myobj);

或

serializetoxml<obj1>(myobj);

借助类型参数推断的神奇之处，您可以完全省略类型参数（但如果您想将其保留在那里则可以）：

serializetoxml(myobj);

Answer 2

尝试以下

public static void serializetoxml(object myobj) {
    XmlSerializer myserializer = new XmlSerializer(myobj.GetType());
    TextWriter mywriter = new StreamWriter("C:\\my.xml");
    myserializer.Serialize(mywriter, myobj);
    mywriter.Close();
}

Answer 3

将方法移动到静态类，并将其设为extension method，如下所示：

internal static class Extensions {
    public static void SerializeToXml<T>(this T myobj)
        {
            XmlSerializer myserializer = new XmlSerializer(typeof(T));
            TextWriter mywriter = new StreamWriter("C:\\my.xml");
            myserializer.Serialize(mywriter, myobj);
            mywriter.Close();
        }
}

您现在可以像使用实例方法一样使用它。您需要将Extensions类放入同一名称空间，或为其添加using指令。

Answer 4

两个选项：

泛型：Serialize<T>(T obj)和typeof(T)
对象：Serialize(object obj)和obj.GetType()

我实际上更喜欢基于苦涩经历的序列化的第二个，但两者都是有效的。

Answer 5

public static void serializetoxml(object myobj)
{
    XmlSerializer myserializer = new XmlSerializer(obj1.GetType());
    TextWriter mywriter = new StreamWriter("C:\\my.xml");
    myserializer.Serialize(mywriter, myobj);
    mywriter.Close();
}

Answer 6

真的没问题。只需使序列化方法适用于泛型类型。请参阅Stack Overflow问题 Using generics with XmlSerializer 。

C＃ - 接受任何类型参数的方法（重用现有方法）

6 个答案: