Question

    override func viewWillAppear(_ animated: Bool) {
    super.viewWillAppear(animated)
    NotificationCenter.default.addObserver(self, selector: #selector(keyboardWillShow(_:)), name: .UIKeyboardWillShow, object: nil)
    NotificationCenter.default.addObserver(self, selector: #selector(keyboardWillHide(_:)), name: .UIKeyboardWillHide, object: nil)
    print("addd observer")

}
override func viewWillDisappear(_ animated: Bool) {
    super.viewWillDisappear(animated)
    NotificationCenter.default.removeObserver(self, name: .UIKeyboardWillShow, object: nil)
    NotificationCenter.default.removeObserver(self, name: .UIKeyboardWillHide, object: nil)
}

func keyboardWillShow(_ sender: Notification) {
    let keyboardSize = (sender.userInfo?[UIKeyboardFrameEndUserInfoKey] as? NSValue)?.cgRectValue
    print("show")
    if(activeTectField != Lable_title && keyboard_status == false)
    {

        boxview.frame.origin.y -= (keyboardSize?.height)!
        keyboard_status = true

    }

}

func keyboardWillHide(_ sender: Notification) {

    let keyboardSize = (sender.userInfo?[UIKeyboardFrameEndUserInfoKey] as? NSValue)?.cgRectValue
    if(keyboard_status == true){
    boxview.frame.origin.y = 0
    boxview.layoutIfNeeded()
    keyboard_status = false
    }

}

我添加了观察者，当键盘弹出时移动视图，它首先工作，但点击几下后，它不起作用。在viewWillAppear()中，已添加观察者，但键盘未弹出，keyboardwillshow()也未被触发。我怎么解决这个问题？欢迎任何建议

Answer 1

为了使用目标/选择器模式，这些方法必须与Objective-C兼容。

使用hystrix-core修饰符前面的键盘方法。

@objc

迅捷的观察者不起作用

1 个答案: