Question

这是正常的：

DEFINE numbers = '1,2,3,4,5';
SELECT * FROM table1 WHERE items IN (&numbers);

就像这样：

SELECT * FROM table1 WHERE items IN ('a','b','c','d'); error

这会返回 snytax错误：

DEFINE letters = 'a','b','c','d';
SELECT * FROM table1 WHERE items IN (&letters);  -- result syntax ERROR

如何使用WHERE ... IN创建的字符串列表来使用DEFINE子句？

Answer 1

将DEFINE值括在双引号中：

define letters = "'a','b','c','d'"

set verify on

select * from dual where dummy in (&letters);

old   1: select * from dual where dummy in (&letters)
new   1: select * from dual where dummy in ('a','b','c','d')

no rows selected

请注意，挑战实际上是如何DEFINE多字符串，因为它是同一个问题：

SQL> define letters = I love kittens
SQL> define letters
DEFINE LETTERS         = "I" (CHAR)

SQL> define letters = 'a','b','c','d'
SQL> define letters
DEFINE LETTERS         = "a" (CHAR)

双引号修复：

SQL> define letters = "I love kittens"
SQL> define letters
DEFINE LETTERS         = "I love kittens" (CHAR)

为了完整起见，设置define变量的另一种方法是使用select方法的column new_value语句。从历史上看，这是为在SQL * Plus报表中动态设置页面标题而提供的，但它在脚本中很方便。（它也是将类型设置为number的唯一方法，而不是它有任何区别。）

SQL> col letters new_value letters
SQL> select q'{'a','b','c','d'}' as letters from dual;

LETTERS
---------------
'a','b','c','d'

1 row selected.

SQL> def letters
DEFINE LETTERS         = "'a','b','c','d'" (CHAR)

SQL> select 123.456 as letters from dual;

   LETTERS
----------
   123.456

1 row selected.

SQL> def letters
DEFINE LETTERS         =    123.456 (NUMBER)

Oracle SQL变量：带有STRING IN子句中值列表的SELECT

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