Question

我需要从导入的csv末尾删除一些冗余的'\ n'，然后才将这些行分成一个数组（否则我会得到额外的空行）。

public function parseCSV(data:String):Array {

    //something to strip linebreaks, \n and \r from end of array

    var lines : Array = data.split ( /\R/ );
    var preamble : Array = lines.splice(0,trashLength);
    var keyArray : Array = lines.splice ( 0, 1 )[0].split ( "," );
    var assocArray : Array = [];
    for each (var line:String in lines)
    {
        var valArray : Array = line.split ( "," );
        var assoc : Object = {};
        for (var i : int = 0; i < keyArray.length; i++)
        {
            var key : String = keyArray[i];
            if (key != null && key != "") assoc[key] = valArray[i];
        }
        assocArray.push ( assoc );
    }

    return assocArray;
}

Answer 1

// normalize line endings to \n, because \r is not recognized as "end of line"
data = data.replace (/\s*\R/g, "\n");  
// remove leading and trailing whitespace
data = data.replace (/^\s*|[\t ]+$/gm, "");

Answer 2

我发现替换仅适用于主题字符串中目标的第一次出现。您可以尝试使用数组拆分/连接。

public static function removeLineBreaks( s:String ) : String 
{ 
    return s.split("\r").join("\n");
}

如果您不想使用分隔符，请将“\ n”替换为“”。

如何从字符串中删除尾随换行符？

2 个答案: