cor中的错误(x,use = use):同时提供' x'并且' y'或类似矩阵' x'

时间:2018-05-29 15:41:44

标签: numeric na psych error-messaging

我正在使用心理包, 我试过以下代码:

library(psych)
str(price_per_d)
Least_appealing <-subset(zdf_base, select=c("price_per_h", 
"price_per_d", "mileage", "one_way_option", "difficulties", 
"vehicle_types", "parking_spot","picking_up","availability", "dirty", 
"returning","refilling", "loalty_programs"))
# code from stackoverflow which I use, to get a numeric x
Least_appealing <- gsub(",", "", Least_appealing)  
Least_appealing <- as.numeric(Least_appealing)

fa.parallel(Least_appealing)

我收到此错误消息:

 > library(psych)
 > str(price_per_d)
 Factor w/ 1 level "Price (daily rate too high)": 1 NA 1 1 1 NA NA 1 1 
 NA ...
 > Least_appealing <-subset(zdf_base, select=c("price_per_h", 
 +                                             "price_per_d", 
 "mileage", "one_way_option", "difficulties", 
 +                                             "vehicle_types", 
 "parking_spot","picking_up","availability", "dirty", 
 +                                             "returning","refilling", 
 "loalty_programs"))
 > 
 > Least_appealing <- gsub(",", "", Least_appealing)  
 > Least_appealing <- as.numeric(Least_appealing)
 **Warnmeldung:
 NAs durch Umwandlung erzeugt** 
> 
> fa.parallel(Least_appealing)
**Fehler in cor(x, use = use) : supply both 'x' and 'y' or a matrix-like 
'x'**
> 

如何成功进行因子分析? 首先我收到了错误消息,我的&#39; x&#39;必须是数字,这就是我使用上述代码的原因。 当我使用这段代码时,R告诉我,我通过转换得到了NA。 我仍然坚持并尝试fa.parallel,这给了我另一个错误信息。 有人可以帮忙吗?

1 个答案:

答案 0 :(得分:0)

我不知道您是否已经解决了这个问题,但是如果您将字符数据与数字数据混合在一起(例如,您的编码是分类的,并且需要将其转换为数字,则可以尝试使用char2numeric函数,然后再使用做fa。

例如包含分类和数值混合数据;

describe(data)  #this will flag those variables that are categorical with an asterix
new.data <- char2numeric(data)  #this makes all numeric
fa(new.data, nfactors=3) #to get three factors

似乎“最小吸引”对象中只有一个变量。