Question

我试图为一系列数字创建一个完美的数字测试，其中n是起始编号，endNum是结束编号。它不会正常循环，但是完美的数字测试（＆＃34;而＃34;循环中的部分）单独工作。我做错了什么？

import java.util.Arrays;
import java.util.Scanner;

public class CodingChallenge3 {

public static void main(String[] args) {

    int n, sum = 0;
    Scanner s = new Scanner(System.in);
    System.out.print("Welcome to the Perfect Number Tester."
                        + "\n" + "Enter a number range."
                        + "\n" + "From: ");
    n = s.nextInt();
    System.out.print("To: ");
    int endNum = s.nextInt();

    while (n <= endNum) {

        for (int i = 1; i < n; i++) {
            if (n % i == 0) {
                sum = sum + i;
            }
        }

        if (sum == n && n != 0) {
            System.out.println(n + " is perfect");
        }

        if (sum > n) {
            System.out.println(n + " is imperfect abundant");
        }

        if (sum < n) {
            System.out.println(n + " is imperfect deficient");
        }

        if (n == 0) {
            System.out.println(n + " has no factors");
        }
        n++;
    }

}

}

Answer 1

您忘记重置n的每个值的总和：

while (n <= endNum) {
    sum = 0; // add this
    for (int i = 1; i < n; i++) {
        if (n % i == 0) {
            sum = sum + i;
        }
    }

    if (sum == n && n != 0) {
        System.out.println(n + " is perfect");
    }

    if (sum > n) {
        System.out.println(n + " is imperfect abundant");
    }

    if (sum < n) {
        System.out.println(n + " is imperfect deficient");
    }

    if (n == 0) {
        System.out.println(n + " has no factors");
    }
    n++;
}

无法在循环中嵌套完美数字测试

1 个答案: