我希望根据之前的查询为每一行加上4个单元格,这会将选择减少到重要的行。
基本上我需要将这两个查询(它们自己工作)结合起来:
SELECT columnx, SUM(`column1`+ `column2` + `column3` + `column4`) as total
FROM table GROUP BY columnx
SELECT * FROM (SELECT * FROM table ORDER BY columny DESC LIMIT 5) t
ORDER BY CASE
when `pos` = 'PG' then 1
when `pos` = 'SG' then 2
when `pos` = 'SF' then 3
when `pos` = 'PF' then 4
else 5
end asc
我试图用第二个查询替换“table”,但它可能不是正确的方法,因为我在这里遇到错误。
SELECT columnx, SUM(`column1`+ `column2` + `column3` + `column4`) as total FROM
(( SELECT * FROM (SELECT * FROM table ORDER BY columny DESC LIMIT 5) t
ORDER BY CASE
when `pos` = 'PG' then 1
when `pos` = 'SG' then 2
when `pos` = 'SF' then 3
when `pos` = 'PF' then 4
else 5
end asc)
GROUP BY columnx
答案 0 :(得分:1)
您应该在第一个查询中为替换SELECT u.columnx, SUM(u.`column1`+ u.`column2` + u.`column3` + u.`column4`) as total
FROM (SELECT t.* FROM (SELECT * FROM table ORDER BY columny DESC LIMIT 5) t
ORDER BY CASE
WHEN t.`pos`='PG' THEN 1
WHEN t.`pos`='SG' THEN 2
WHEN t.`pos`='SF' THEN 3
WHEN t.`pos`='PF' THEN 4
ELSE 5
END ASC) u GROUP BY u.columnx
的块创建别名。
public static int countWords(char[] array) {
boolean isSpace = true;
int count = 0;
for (int i=0; i < array.length; ++i) {
if (array[i] != ' ' && isSpace) {
++count;
isSpace = false;
}
else if (array[i] == ' ') {
isSpace = true;
}
}
return count;
}