将两个Mysql SUM select查询合并到一个查询中

Question

我在下面有两个查询的SUM值 查询1：*

  

SELECT SUM（price）FROM TABLE1 WHERE acc_id ='555'

查询2：

  

SELECT SUM（price）FROM TABLE2 WHERE account ='555'＆amp;＆amp;活性= '1'

我尝试合并这两个查询，但提供了错误的和结果，例如query1 sum is: -86500和Query2 sum is: 76000，结果必须为-10500，但结果显示的数字为{{1} }

我正在尝试这样，但我没有得到预期的结果。

-486000

表格图片：

Answer 1

由于加入，记录的数量会重复，并且您获得更高的总和值 试试这个

SELECT sum(prc) 
FROM (
    SELECT SUM(price) prc FROM TABLE1 WHERE acc_id = '555'
    union all 
    SELECT SUM(price) prc FROM TABLE2 WHERE account = '555' && active='1'
) a

Answer 2

试试这个

SELECT SUM(C.TOTAL) AS TOTAL_CREDIT FROM (SELECT SUM(A.price) AS TOTAL FROM TABLE1 A WHERE A.acc_id = '555'
UNION ALL
SELECT SUM(B.price) AS TOTAL FROM TABLE2 B WHERE B.account = '555' && B.active='1') C;

Answer 3

试试这个

  SELECT (t1.price + t2.price) AS TotalCredit 
    FROM TABLE1 AS t1, TABLE2 AS t2 
    WHERE t1.`acc_id` = '555' && t2.`Account`='555' && t2.`Active`='1'

编辑：

这里你想要的是什么

 SELECT (SUM(t1.price)+SUM(t2.price) )/2  AS TotalCredit 
FROM Table1 AS t1, Table2 AS t2 
WHERE t1.`acc_id` = '555' && t2.`account`='555' && t2.`active`='1'

DEMO FIDDLE HERE

Answer 4

试试

SELECT (SUM(t1.price) + SUM(t2.price)) AS TotalCredit 
FROM TABLE1 AS t1, TABLE2 AS t2 
WHERE t1.`acc_id` = '555' && t2.`Account`='555' && t2.`Active`='1'

Answer 5

这个怎么样：

SELECT SUM(a) 
FROM
  (SELECT SUM(price) AS a
   FROM TABLE1 
   WHERE acc_id = '555'
   UNION ALL
   SELECT SUM(price) AS a
   FROM TABLE2 
   WHERE account = '555' && active='1')

Answer 6

Join可能会更好。 :)如果你能向我们展示表模式，那会更好。这是基于某些假设的样本数据的解决方案。

示例数据：

表1：

ID  PRICE
11  200
55  300
33  200
44  100
55  500

表2：

ID  PRICE   ACTIVE
1   200     0
2   300     1
55  200     0
55  100     1
55  400     1

• SQLFIDDLE DEMO

查询：

select sum(t.price) + x.tb2credit
from tb1 as t
inner join
(SELECT id, SUM(price) AS Tb2Credit 
FROM tb2
WHERE id = 55
and `Active`=1) x
on t.id = x.id

结果：

SUM(T.PRICE) + X.TB2CREDIT
1300