Question

如何返回保存到数据库中的注释，以便在.done（）函数中使用它，这样我可以在不刷新页面的情况下显示该注释？

CommentController：

namespace App\Http\Controllers;

use Illuminate\Http\Request;
use App\Comment;

class CommentsController extends Controller
{
    public function postComment(Request $request){
        $userId = $request['userId'];
        $imageId = $request['imageId'];
        $commentText = $request['comment'];

        $comment = new Comment();
        $comment->user_id = $userId;
        $comment->image_id = $imageId;
        $comment->comment = $commentText;
        $comment->save();
    }
}

JavaScript的：

$('.postComment').on('click', function(event){
        event.preventDefault();
        var userId = $("input[name=user_id]").val();
        var imageId = $("input[name=image_id]").val();
        var comment = $("textarea[name=comment]").val();

        $.ajax({
            method: 'POST',
            url: urlComment,
            data: {userId: userId, imageId: imageId, comment: comment, _token: token}
        }).done(function(serverResponseData){
            $("textarea[name=comment]").val("");
            $('.comments').append('<p></p>');
        })
    });

Answer 1

你可以通过返回json共振来访问ajax中的done方法中的数据返回

 public function postComment(Request $request){
    $userId = $request['userId'];
    $imageId = $request['imageId'];
    $commentText = $request['comment'];

    $comment = new Comment();
    $comment->user_id = $userId;
    $comment->image_id = $imageId;
    $comment->comment = $commentText;
    $comment->save();
    return response()->json(['comment'=>$comment]);
}

Answer 2

您可以返回评论，它将在serverResponseData上你只需要在方法的返回时添加它：

 public function postComment(Request $request){
    $userId = $request['userId'];
    $imageId = $request['imageId'];
    $commentText = $request['comment'];

    $comment = new Comment();
    $comment->user_id = $userId;
    $comment->image_id = $imageId;
    $comment->comment = $commentText;
    $comment->save();
    return $comment;
}

之后serverResponseData将保存该值，如果您希望它像访问数组那样访问它，您可以将ajax的返回类型设置为json： dataType：'json' < / p>

如何从我的控制器正确返回注释并在.done（）AJAX函数中使用它？

2 个答案: