Question

我尝试将我的数组传递给外部函数失败了吗？以下是jsbin中的工作代码：https://jsbin.com/kugesozawi/edit?js,console,output结果应该传递给returnSearch。

var googleSuggest = function(returnSearch){

  var term = $('#searchInput').val();
  var result = [];
  var service = {
    youtube: { client: 'youtube', ds: 'yt' },
    books: { client: 'books', ds: 'bo' },
    products: { client: 'products-cc', ds: 'sh' },
    news: { client: 'news-cc', ds: 'n' },
    images: { client: 'img', ds: 'i' },
    web: { client: 'hp', ds: '' },
    recipes: { client: 'hp', ds: 'r' }
  };

  $.ajax({
    url: 'https://clients1.google.com/complete/search',
    dataType: 'jsonp', 
    data: {
      q: term,
      nolabels: 't',
      client: service.web.client,
      ds: service.web.ds
    } 
  }).done(function(data) {

      result.pop()

      $.each(data[1], function(item, value) {

        var stripedValue = value[0].replace(/<[^>]+>/g, '');

           result.push(stripedValue); 

      })

      console.log(result)

    })

  returnSearch = ['ActionScript', 'AppleScript', 'Asp']

  return returnSearch

};

Answer 1

我认为让它返回你想要的值的唯一方法是使调用同步，这意味着无论何时调用ajax调用，你都必须等待它准备就绪（你通常会这样做）不想要）。您可以在结果调用中调用returnSearch函数，如下所示：

  var googleSuggest = function(returnSearch){
  var term = $('#searchInput').val();
  var service = {
    youtube: { client: 'youtube', ds: 'yt' },
    books: { client: 'books', ds: 'bo' },
    products: { client: 'products-cc', ds: 'sh' },
    news: { client: 'news-cc', ds: 'n' },
    images: { client: 'img', ds: 'i' },
    web: { client: 'hp', ds: '' },
    recipes: { client: 'hp', ds: 'r' }
  };

 var promise = $.ajax({
    url: 'https://clients1.google.com/complete/search',
    dataType: 'jsonp', 
    data: {
      q: term,
      nolabels: 't',
      client: service.web.client,
      ds: service.web.ds
    } 
  })

  return promise
};


$(function() {  
  $('#searchInput').autoComplete({
    minChars: 1,
    source: function(term, suggest){
      var promise = googleSuggest()
      returnSearch = function(term, choices) {
        console.log(choices)
        var suggestions = [];
        for (i=0;i<choices.length;i++)
         if (~choices[i].toLowerCase().indexOf(term)) suggestions.push(choices[i]);
          suggest(suggestions);
      }

      $.when(promise).then(function(data) {
        term = term.toLowerCase();
        var result = [];
        $.each(data[1], function(item, value) {
          var stripedValue = value[0].replace(/<[^>]+>/g, '');
             result.push(stripedValue); 
        })
        returnSearch(term, result)
      })
    }
  });  
})

另见this stackoverflow post。

如何从我的函数传递数组返回

1 个答案: