Question

我认为另一次我错误地提出了我的问题enter link description here

我有一个文件.txt，就像这样：

int main(){
    int dp[3][3];
    string A,B;
    string array[] = {"axd","byd","axd"};
    for (int i = 0 ; i < 3; i++){
        A = array[i];

        for (int j = 0; j<3; j++){
            B = array [j];
            if(A[i] == B[j]){
                dp[i][j] =1;
                cout << dp[i][j] << endl;
            }else
                dp[i][j] = 0;
        }
    }
    for(int i = 0; i<3; i++){
        for(int j = 0; j<3; j++){
            //cout << dp[i][j];
        }

        //cout << endl;
    }
    return 0;
}

我想提取行中的一部分并提取每个列表的每个元素，这是我的脚本：

.
.
T - Python and Matplotlib Essentials for Scientists and Engineers
.
A - Wood, M.A.
.
.
.

和我想要的输出：

with open('file.txt','r') as f:
    for line in f:
        if "T - " in line:
            o_t = line.rstrip('\n')
        elif "A - " in line:
            o_a = line.rstrip('\n')

o_T = filter(None, o_t.split('T - '))
list_o_T = [o_T]
o_Title = list_o_T[0]
print (o_Title)

o_A = filter(None, o_a.split('A - '))
list_o_A = [o_A]
o_Lname = list_o_A[0]
o_Fname = list_o_A[1]
print (o_Lname)
print (o_Fname)

Answer 1

我按如下方式输入脚本：

#!/usr/bin/env python3.6
from pathlib import Path

def main():
    for line in Path('file.txt').read_text().split('\n'):
        if 'T - ' in line:
            o_t = line.replace('T - ', '')
        elif 'A - ' in line:
            o_Lname, o_Fname = line.replace('A - ', '').split(', ')

    print(o_t)
    print(o_Lname)
    print(o_Fname)

if __name__ == '__main__':
    main()

输出：

Python and Matplotlib Essentials for Scientists and Engineers
Wood
M.A.

在读取文件后使用Python提取每个列表的每个元素

1 个答案: