实施智能TicTacToe对手

Question

我是初学者试图在java中创建一个tictactoe游戏，我需要创建两个特定的方法，一个是对手随机玩，另一个是积极玩“智能”，试图在每个回合中积极获胜。登记/>   我的问题来自主动播放方法，因为我不知道如何从这个开始。

import javax.swing.JOptionPane;

public class Tictactoe
{
String table[][];    
boolean winner;
public Tictactoe()
{
    table = new String[3][3];
    for(int x = 0; x < 3; x++)
    {
        for(int y = 0; y < 3; y++)
        {
            table[x][y] = " ";
            int xUser;
            int yUser;
            int xMac;
            int yMac;
        }
    }
}

public void board()
{ 
    System.out.println("-----------");
    for(int x = 0; x < 3; x++)
    {

        System.out.print("| ");
        for(int y = 0; y < 3; y++)
        {

            System.out.print(table[x][y] + " | ");
        }

        System.out.println();

    }
    System.out.println("-----------");
}

public void playRandom()
{
    int x;
    int y;
    int xMaq;
    int yMaq;
    boolean winner = false;
    while(!winner)
    {
        move();                    
    }
    if(winner = true)
    {
        new Tictactoe();

}

public void findWinnerMach()
{
    if (table[0][0]== "O" && table[0][1]== "O" && table [0][2]== "O") {
        JOptionPane.showMessageDialog(null, "You lose");
        winner = true;       
        board();
        System.exit(0);
    }
    if (table[1][0]== "O" && table[1][1]== "O" && table [1][2]== "O") {
        JOptionPane.showMessageDialog(null, "You lose");
        winner = true;
        board();
        System.exit(0);
    }
    if (table[2][0]== "O" && table[2][1]== "O" && table [2][2]== "O") {
        JOptionPane.showMessageDialog(null, "You lose");
        winner = true;
        board();
        System.exit(0);
    }
    if (tabla[0][0]== "O" && tabla[1][0]== "O" && tabla [2][0]== "O") {
        JOptionPane.showMessageDialog(null, "You lose");
        winner = true;
        board();
        System.exit(0);
    }
    if (table[0][1]== "O" && table[1][1]== "O" && table [2][1]== "O") {
        JOptionPane.showMessageDialog(null, "You lose");
        winner = true;
        board();
        System.exit(0);
    }
    if (table[0][2]== "O" && table[1][2]== "O" && table [2][2]== "O") {
        JOptionPane.showMessageDialog(null, "You lose");
        winner = true;
        board();
        System.exit(0);
    }        
    if (table[0][0]== "O" && table[1][1]== "O" && table [2][2]== "O") {
        JOptionPane.showMessageDialog(null, "You lose");
        winner = true;
        board();
        System.exit(0);
    }
    if (table[0][2]== "O" && table[1][1]== "O" && table [2][0]== "O") {
        JOptionPane.showMessageDialog(null, "You lose");
        winner = true;
        board();
        System.exit(0);
    }

}

public void findWinnerUser()
{
    if (table[0][0]== "X" && table[0][1]== "X" && table [0][2]== "X") {
        JOptionPane.showMessageDialog(null, "You win!");
        winner = true;
        board();
        System.exit(0);
    }
    if (table[1][0]== "X" && table[1][1]== "X" && table [1][2]== "X") {
        JOptionPane.showMessageDialog(null, "You win!");
        winner = true;
        board();
        System.exit(0);
    }
    else if (table[2][0]== "X" && table[2][1]== "X" && table [2][2]== "X") {
        JOptionPane.showMessageDialog(null, "You win!");
        winner = true;
        board();
        System.exit(0);
    }
    if (table[0][0]== "X" && table[1][0]== "X" && table [2][0]== "X") {
        JOptionPane.showMessageDialog(null, "You win!");
        winner = true; 
        board();
        System.exit(0);
    }
    if (table[0][1]== "X" && table[1][1]== "X" && table [2][1]== "X") {
        JOptionPane.showMessageDialog(null, "You win!");
        winner = true
        board();
        System.exit(0);
    }
    if (table[0][2]== "X" && table[1][2]== "X" && table [2][2]== "X") {
        JOptionPane.showMessageDialog(null, "You win!");
        winner = true;
        board();
        System.exit(0);
    }
    if (table[0][0]== "X" && table[1][1]== "X" && table [2][2]== "X") {
        JOptionPane.showMessageDialog(null, "You win!");
        winner = true;
        board();
        System.exit(0);
    }
    if (table[0][2]== "X" && table[1][1]== "X" && table [2][0]== "X") {
        JOptionPane.showMessageDialog(null, "You win!"); 
        winner = true;
        board();
        System.exit(0);
    }
}

public void move()
{
    int xUser;
    int yUser;
    int xMac;
    int yMac;        
    xUser = Integer.parseInt(JOptionPane.showInputDialog("Type a row from 0 to 2"));
    yUser = Integer.parseInt(JOptionPane.showInputDialog("Type a column from 0 to 2"));       
    if(table[xUser][yUser] == "X" || tabla[xUser][yUser] == "O" ) {
        xUser = Integer.parseInt(JOptionPane.showInputDialog("Selected slot is taken, select a new row"));
        yUser = Integer.parseInt(JOptionPane.showInputDialog("Selected slot is taken, select a new column"));
    }
    else
    {
        table[xUser][yUser] = "X";
    } 
    table[xUser][yUser] = "X";

    JOptionPane.showMessageDialog(null,"CPU moves");
    xMac = (int)(Math.random()*3)+0;
    yMac = (int)(Math.random()*3)+0;      
    if(table[xUser][yUser] == "O" || table[xUser][yUser] == "X" ) {
        xUser = (int)(Math.random()*3)+0;
        yUser = (int)(Math.random()*3)+0;
        table[xUser][yUser] = "O";
    }              
    findWinnerUser();
    findWinnerMac();
    board();
}

public void playSmart()
{

}
}

大多数情况下仍然有很多工作需要改进，需要修改一些东西，但是，我不想这样做，直到我有一套方法，想法或计划实施这种“智能”方法以防万一到目前为止，我非常错误，不胜感激。