Question

我有一个JSON数组，我想从（使用jq）中提取值：

这是一个简化的例子

{
  "query": "",
  "results": [
  {
      "id": 111,
      ...
      "buyer": {
        "email": "mail1@mail.com",
        ...
        "billing_info": {
          "doc_number": "123"
        }
      }
    },
    {
      "id": 222,
      ...
      "buyer": {
        "email": "mail2@mail.com",
        ...
        "billing_info": {
          "doc_number": "456"
        }
      }
    }
  ]
}

目前，我正在使用此过滤器：

{user: .results[].id, mail: .results[].buyer.email, buyer: .results[].buyer.billing_info.doc_number}

我正在进行全面加入＆＃34;结果。

{"user":111,"mail":"mail1@mail.com","buyer":"123"}
{"user":111,"mail":"mail1@mail.com","buyer":"456"}
{"user":111,"mail":"mail2@mail.com","buyer":"123"}
{"user":111,"mail":"mail2@mail.com","buyer":"456"}
{"user":222,"mail":"mail1@mail.com","buyer":"123"}
{"user":222,"mail":"mail1@mail.com","buyer":"456"}
{"user":222,"mail":"mail2@mail.com","buyer":"123"}
{"user":222,"mail":"mail2@mail.com","buyer":"456"}

我想要的是从完整对象中过滤一些字段。所以在这个例子中，我有2个对象，所以我想要2个结果：

{"user":111,"mail":"mail1@mail.com","buyer":"123"}
{"user":222,"mail":"mail2@mail.com","buyer":"456"}

以下是我的示例摘录：

https://jqplay.org/s/nM1WzWRmnK

谢谢大家！

Answer 1

你只需要将迭代器（.results[]）“提升”到前面：

.results[] 
| {user: .id, mail: .buyer.email, buyer: .buyer.billing_info.doc_number}

使用-c命令行选项，会产生：

{"user":111,"mail":"mail1@mail.com","buyer":"123"}
{"user":222,"mail":"mail2@mail.com","buyer":"456"}

将jq中的(ARRAY[] | ...)视为与其他语言中的for (x in ARRAY) {...}类似，可能会有所帮助。

jq json数组混合（重复）结果

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