Question

鉴于此输入

{
  "data": [
    {
      "id": "001",
      "metadata": {
        "item1": 1
      },
      "records": [
        {
          "name": "name1",
          "type": "type1"
        },
        {
          "name": "name2",
          "type": "type2"
        }
      ]
    },
    {
      "id": "002",
      "metadata": {
        "item1": 1
      },
      "records": [
        {
          "name": "name1",
          "type": "type1"
        }
      ]
    },
    {
      "id": "003",
      "metadata": {},   
      "records": [
        {
          "name": "name1",
          "type": "type1"
        },
        {
          "name": "name2",
          "type": "type2"
        }
      ]
    }
  ]
}

我想输出这个

[
  {
    "id": "001",
    "Item1": 1,
    "Name": "name2"
  },
  {
    "id": "002",
    "Item1": 1,
    "Name": null
  },
  {
    "id": "003",
    "Item1": null,
    "Name": "name2"
  }
]

然而使用此

jq '[.data[] | {id, "Item1": .metadata.item1, "Name": .records[] | select(.type == "type2").name}]'

jq查询我得到了这个

[
  {
    "id": "001",
    "Item1": 1,
    "Name": "name2"
  },
  {
    "id": "003",
    "Item1": null,
    "Name": "name2"
  }
]

我怎样才能获得＆＃39; 002＆＃39; id对象也输出？我已经尝试了各种if if else条件语句，但无济于事。

Answer 1

我对map很新，所以这可能不是最佳解决方案。

如果select将[ .data[] | { id : .id, Item1 : .metadata.item1, Name : .records | map(select(.type == "type2"))[0].name } ]改为记录数组，则不会删除周围的对象。例如：

parse.jq

jq -f parse.jq file.json

像这样运行：

[
  {
    "id": "001",
    "Item1": 1,
    "Name": "type2"
  },
  {
    "id": "002",
    "Item1": 1,
    "Name": null
  },
  {
    "id": "003",
    "Item1": null,
    "Name": "type2"
  }
]

输出：

Volunteers:
VID - ID of volunteer
ActiveGroups - Multivalue list of VolunteerGroups that they're active in
InterestGroupss - Multuvalue list of VolunteerGroups that they are interested in

VolunteerGroups:
ID - ID of group
GroupName - name of group

Answer 2

可能是因为第二个嵌套数组不满足条件

select(.type == "type2")

从嵌套数组中选择

2 个答案: