Question

我有2张桌子： -user_activity：包含ID活动和ID用户 -activity：包含Id，Id用户等...

我想只显示2个表中的活动

有我的代码： -activities包含用户的所有活动 -usersactivities_id在一个选项卡中包含用户的所有user_activity（例如：10,2,3）

  def fetch_maj_activities
    user = current_user
    activities = []
    user.groups.each do |group|
      activities << Activity.where(group: group)
    end


    usersactivities_id = current_user.user_activities.select('activity_id').map(&:activity_id).uniq

    activities.each do |activity|
      if usersactivities_id.include? activity.id
      else
        activities = activities.flatten.reject {|a| a.id == activity.id}
      end
    end
    @all_activities = activities.flatten.sort_by(&:updated_at).reverse
    respond_to do |format|
      format.js
    end
  end

日志：

  CACHE Activity Load (0.0ms)  SELECT  "activities".* FROM "activities" WHERE "activities"."group_id" = $1 LIMIT $2  [["group_id", 1], ["LIMIT", 11]]
  ↳ /home/benjamin/.rbenv/versions/2.5.0/lib/ruby/gems/2.5.0/gems/activerecord-5.2.0.rc1/lib/active_record/log_subscriber.rb:98
NoMethodError (undefined method `id' for #<ActiveRecord::Relation []>
Did you mean?  ids):

app/controllers/activities_controller.rb:65:in `block in fetch_maj_activities'
app/controllers/activities_controller.rb:64:in `each'
app/controllers/activities_controller.rb:64:in `fetch_maj_activities'

Answer 1

有答案，为我工作:)

  def fetch_maj_activities

    user = current_user
    activities = []
    usersactivities_id = current_user.user_activities.select('activity_id').map(&:activity_id).uniq

    user.groups.each do |group|
      activities << Activity.where(group: group)
    end



    usersactivities_id.each do |useractid|
      activities.flatten.each do |act|
        if act.id == useractid
          activities = activities.reject {|a|a}

        end
      end
    end

    @all_activities = activities.flatten.sort_by(&:updated_at).reverse
    respond_to do |format|
      format.js {render :action => "fetch_activities"}
    end
  end

导轨|我想只展示一些文章

1 个答案: