Question

我一直在引用this rails教程，尝试创建一个Feed，其中只有属于已接受我朋友请求的用户的文章会显示在我的Feed中。

但是，我在教程中有一个不同的架构和用户模型（我有一个额外的步骤，其中有待接受的朋友请求）。我的用户模型中的以下方法不会过滤掉尚未被接受的友谊，因此未经证实的朋友的文章会出现在我的Feed中，这不是我想要的。

user.rb

  has_many :friendships
  has_many :received_friendships, class_name: "Friendship", foreign_key: "friend_id"
  has_many :active_friends, -> { where(friendships: { accepted: true}) }, through: :friendships, source: :friend
  has_many :received_friends, -> { where(friendships: { accepted: true}) }, through: :received_friendships, source: :user
  has_many :pending_friends, -> { where(friendships: { accepted: false}) }, through: :friendships, source: :friend
  has_many :requested_friendships, -> { where(friendships: { accepted: false}) }, through: :received_friendships, source: :user

  def feed
    friend_ids = "SELECT friend_id FROM friendships
                     WHERE  user_id = :user_id"
    Article.where("user_id IN (#{friend_ids})
                     OR user_id = :user_id", user_id: id)
  end

schema.rb

  create_table "friendships", force: :cascade do |t|
    t.integer "user_id"
    t.integer "friend_id"
    t.boolean "accepted", default: false
    t.datetime "created_at", null: false
    t.datetime "updated_at", null: false
  end

页面控制器

def home
    @feed = current_user.feed.all
end

home.html.erb

<%= render @feed %>

Answer 1

对于你的情况我认为密钥在这里WHERE（user_id =：user_id AND accepted = true），我从友谊架构中获得了接受的字段。

  def feed
    friend_ids = "SELECT friend_id FROM friendships
                     WHERE (user_id = :user_id AND accepted = 't')"
    Article.where("user_id IN (#{friend_ids})
                     OR user_id = :user_id", user_id: id)
  end

自定义Feed仅显示来自关注用户的文章

1 个答案: