Question

我使用filterrific进行过滤。

假设我得到一个locality设置为＆＃34;纽约＆＃34;的对象。

使用现有代码，如果我只搜索一个单词，它就可以工作：＆＃34; New＆＃34;。如果我写'＃34;纽约＆＃34;，什么都没有。

在filterrific示例中，过滤器允许用户在＆＃34;查询＆＃34;中写入多个单词。

模型

  scope :search_query, lambda { |query|
  return nil  if query.blank?
    terms = query.downcase.split(/\s+/)
    terms = terms.map { |e|
      (e.gsub('*', '%') + '%').gsub(/%+/, '%')
    }
    num_or_conds = 2
    where(
      terms.map { |term|
        "(LOWER(title) LIKE ? OR LOWER(locality) LIKE ?)"
      }.join(' AND '),
      *terms.map { |e| [e] * num_or_conds }.flatten
    )
  }



filterrific(
   default_filter_params: {},
   available_filters: [
     :search_query
   ]
 )

控制器

def index
   @filterrific = initialize_filterrific(
     @ads,
     params[:filterrific]
   ) or return
    @ads = @filterrific.find.page(params[:page])
end

查看

  = form_for_filterrific @filterrific do |f|
    div
      | Search
      = f.text_field :search_query, class: 'skills field w-input filterrific-periodically-observed', placeholder: "Job title, keywords, skills..."

      = f.submit 'GO !', {class: "submit-b w-button"}

修改

日志

 Ad Load (1.2ms)  SELECT  "ads".* FROM "ads" WHERE (publishing_at <= '2018-05-24') AND (expiring_at >= '2018-05-24') AND ((LOWER(title) LIKE 'new%' OR LOWER(locality) LIKE 'new%') AND (LOWER(title) LIKE 'york%' OR LOWER(locality) LIKE 'york%')) LIMIT $1 OFFSET $2  [["LIMIT", 20], ["OFFSET", 0]]

Answer 1

可以从SQL日志中看到问题：

...
AND ((LOWER(title) LIKE 'new%' OR LOWER(locality) LIKE 'new%')
AND (LOWER(title) LIKE 'york%' OR LOWER(locality) LIKE 'york%'))

所需的SQL 应：

...
AND ((LOWER(title) LIKE '%new%' OR LOWER(locality) LIKE '%new%')
AND (LOWER(title) LIKE '%york%' OR LOWER(locality) LIKE '%york%'))

因为＆＃34;新＆＃34;位于locality的 start ，它匹配;但因为＆＃34;约克＆＃34;不是一开始，它不匹配。

要解决此问题，您可以替换以下行：

(e.gsub('*', '%') + '%').gsub(/%+/, '%')

使用：

('%' + e.gsub('*', '%') + '%').gsub(/%+/, '%')

filterrific：如何用多个单词搜索查询？

1 个答案: