Question

在我的应用程序中，我正在scope/search上:title对我的记录进行搜索/过滤。搜索本身工作正常，唯一的事情是用户需要准确写出title＆amp;他们无法在:title内搜索单词。

例如，如果title是： 此搜索很酷，则用户需要开始搜索并拥有完整的句子：此搜索进行搜索，他们无法撰写很酷并获得标题中很酷的记录。

我的scope看起来像是：

class Post < ActiveRecord::Base

  scope :search_query, lambda { |query|
    return nil  if query.blank?
    # condition query, parse into individual keywords
    terms = query.downcase.split(/\s+/)
    # replace "*" with "%" for wildcard searches,
    # append '%', remove duplicate '%'s
    terms = terms.map { |e|
      (e.gsub('*', '%') + '%').gsub(/%+/, '%')
    }
    # configure number of OR conditions for provision
    # of interpolation arguments. Adjust this if you
    # change the number of OR conditions.
    num_or_conditions = 1
    where(
        terms.map {
          or_clauses = [
              "LOWER(posts.title) LIKE ?"
          ].join(' OR ')
          "(#{ or_clauses })"
        }.join(' AND '),
        *terms.map { |e| [e] * num_or_conditions }.flatten
    )
  }

如何制作我的scope/query，以便用户可以搜索title中的字词并获取包含他们搜索过的字词的记录？

我尝试使用ILIKE，但之后搜索停止在开发，我认为因为sqlite而不能ILIKE，但是production搜索有效，但仍然无法搜索标题中的字词。

当我使用LIKE时，sql查询是：

SELECT COUNT(count_column) FROM (SELECT  1 AS count_column FROM "posts" WHERE ((LOWER(posts.title) LIKE 'rails%')) LIMIT 50 OFFSET 0) subquery_for_count

当我使用ILIKE时，查询是：

SELECT COUNT(count_column) FROM (SELECT  1 AS count_column FROM "posts" WHERE ((LOWER(posts.title) ILIKE 'rails%')) LIMIT 50 OFFSET 0) subquery_for_count

SQLite3::SQLException: near "ILIKE": syntax error: SELECT COUNT(count_column) FROM (SELECT  1 AS count_column FROM "posts" WHERE ((LOWER(posts.title) ILIKE 'rails%')) LIMIT 50 OFFSET 0) subquery_for_count

ps：我正在使用Filterrific gem

我将pg gem用于Production ENV＆amp; sqlite3

的Development ENV

Answer 1

正如此w3schools article中所述，WHERE CustomerName LIKE 'a%' => Finds any values that starts with "a" WHERE CustomerName LIKE '%a' => Finds any values that ends with "a" WHERE CustomerName LIKE '%or%' => Finds any values that have "or" in any position WHERE CustomerName LIKE '_r%' => Finds any values that have "r" in the second position WHERE CustomerName LIKE 'a_%_%' => Finds any values that starts with "a" and are at least 3 characters in length WHERE ContactName LIKE 'a%o' => Finds any values that starts with "a" and ends with "o"的作用如下：

(e.gsub('*', '%') + '%').gsub(/%+/, '%')

我需要将('%' + e.gsub('*', '%') + '%').gsub(/%+/, '%')，更改为： (e.gsub('*', '%') + '%').gsub(/%+/, '%')。

使用(LOWER(posts.title) ILIKE 'keyword%')进行搜索时，结果为('%' + e.gsub('*', '%') + '%').gsub(/%+/, '%') ，而(LOWER(posts.title) ILIKE '%keyword%')则为{{1}}

Ruby on Rails - 搜索标题

1 个答案: