Question

所以我在示例列表中有这个有问题的字符串：

pM = ['sam DM @carl hello friends do you know each other, @james?']

我需要一种方法在“@”符号之后打印两个名称到目前为止我只能想出如何打印一个IE：

def mentioned():
    for s in pM:
        if "@" in s:
            userName = s.split()
            single = (userName[3])
            data.append(single)
        else:
            None

Answer 1

使用正则表达式：

import re
pM = ["sam DM @carl hello friends do you know each other", "@james?"]
for i in pM:
    print(re.findall("\@[a-z]+", i)[0])

<强>输出：

@carl
@james

Answer 2

你也可以试试这个：

import re
pM = ['sam DM @carl hello friends do you know each other, @james?']
list1 = pM[0].split(' ')
x = [ele for ele in list1 if re.split('@', ele) and '@' in ele]           # This will filter the strings with '@' in it
for name in x:
    print(re.split('@', name)[1])         # This prints only the names 'carl', 'james'

输出：

['@carl', '@james?']
carl
james

如果您不想使用import re，请使用以下代码：

 for ele in pM[0].split():
    if '@' in ele or '?' in ele:
        print(ele.strip('@?'))

输出：

carl
james

在看到“@”字符后打印字符串

2 个答案: