Question

我想看看在最后一次出现某个字符后两个字符串是否相互匹配。例如：

same_list = ['Time - is an illusion.', 'Lunchtime - which is delicious - is an illusion.']

True

所以在这种情况下，我的某个角色是' - '。我想看看两个字符串的最后一个' - '之后的字符串是否相互匹配。 ' - '之后的字符串是'幻觉'。两个字符串。这是真的。

到目前为止，我有：

same_list = ['Time - is an illusion.', 'Lunchtime - which is delicious - is an illusion.']

some_list = []

for string in same_list:
    for ch in string:
        if ch == '-':
            new_string = string.split(ch)
            some_list.append(new_string)

i = 0

for sublist[-1] in some_list:

我觉得我忘记了在python中执行此操作的更简单方法。我所能记住的只是while循环，但这将返回第一次出现' - '，而不是最后一次出现。此外，我写的函数返回第二个字符串两次，因为它被拆分两次。我该如何摆脱它？

Answer 1

你可以做这样简单的事情（假设列表中的所有结尾都必须匹配）：

def end_matches(*phrases):           # phrases becomes a tuple that will take any number
    phrase_endings = set()           # number of positional parameters
    for phrase in phrases:
        end = phrase.split('-')[-1]  # take the last element of the split list
        phrase_endings.add(end)
    return len(phrase_endings) == 1  # the set holds only unique values, so a set of
                                     # length 1 means all values in the set are the same

您现在可以测试一下：

>>> same_list = ['Time - is an illusion.', 'Lunchtime - which is delicious - is an illusion.']
>>> end_matches(*same_list)          # unpack the list into individual positional arguments
True

字符串在某个字符后匹配

1 个答案: