Question

我有2个词典列表：namedLabels

[{"id":"2","image":"45-14.png","name":"test2","xMax":"4784","xMin":"4767","yMax":"64","yMin":"57"},{"id":"5","image":"45-14.png","name":"test5","xMax":"4896","xMin":"4852","yMax":"64","yMin":"59"}]

和otherLabels

[{"id":"1","image":"45-14.png","name":"","xMax":"4760","xMin":"4751","yMax":"64","yMin":"59"},{"id":"3","image":"45-14.png","name":"","xMax":"4830","xMin":"4791","yMax":"67","yMin":"57"},{"id":"4","image":"45-14.png","name":"","xMax":"4845","xMin":"4837","yMax":"64","yMin":"57"},{"id":"6","image":"45-14.png","name":"","xMax":"4914","xMin":"4902","yMax":"67","yMin":"57"}]

我想要做的是：如果namedLabels的正方形完全覆盖了otherLabels的正方形，就像完全覆盖它一样，我想要id通讯员otherLabels元素打印（在控制台中）。

我的代码：

for (i = 0; i < namedLabels.length; i++) {
    for (i = 0; i < otherLabels.length; i++) {
      if ((otherLabels[i].xMin<namedLabels[i].xMin) && (otherLabels[i].xMax<namedLabels[i].xMax) &&
          (otherLabels[i].yMin<namedLabels[i].yMin) && (otherLabels[i].yMax<namedLabels[i].yMax)) {
        console.log (otherLabels[i].id)
      }
    }
  }

我在共享剪辑的第3行上遇到的错误：

Uncaught TypeError: Cannot read property 'xMin' of undefined
    at HTMLCanvasElement.c.onclick

Answer 1

您对内部和外部循环使用相同的变量i。将内部for循环的变量更改为j，它可以正常工作：

＆＃13;

var namedLabels = [{"id":"2","image":"45-14.png","name":"test2","xMax":"4784","xMin":"4767","yMax":"64","yMin":"57"},{"id":"5","image":"45-14.png","name":"test5","xMax":"4896","xMin":"4852","yMax":"64","yMin":"59"}]
var otherLabels = [{"id":"1","image":"45-14.png","name":"","xMax":"4760","xMin":"4751","yMax":"62","yMin":"50"},{"id":"3","image":"45-14.png","name":"","xMax":"4830","xMin":"4791","yMax":"67","yMin":"57"},{"id":"4","image":"45-14.png","name":"","xMax":"4845","xMin":"4837","yMax":"64","yMin":"57"},{"id":"6","image":"45-14.png","name":"","xMax":"4914","xMin":"4902","yMax":"67","yMin":"57"}]

for (i = 0; i < namedLabels.length; i++) {
    for (j = 0; j < otherLabels.length; j++) {
      if ((otherLabels[j].xMin<namedLabels[i].xMin) && (otherLabels[j].xMax<namedLabels[i].xMax) &&
          (otherLabels[j].yMin<namedLabels[i].yMin) && (otherLabels[j].yMax<namedLabels[i].yMax)) {
        console.log (otherLabels[j].id)
      }
    }
  }

＆＃13;

为什么我不能打印重叠矩形的id？

1 个答案: