Question

您好我已经向http服务器发出了请求作为事件服务。此服务器将事件作为分块数据发送。因为有不同的事件，我得到了不同的JSON文档。问题1.如果每次获得新数据时如何读取此数据，而不仅仅是连接已关闭？问题2.如何根据事件解析不同对象中的JSON并将其作为返回类型？

http流看起来像：

GET /OTEvents?subscriptionId=eyJhbGciOiJIUzI1NiJ9.eyJzdWIiOiJhZG1pbiIsImlhdCI6MTUyNzY2MTg0MX0.fxsP4bLNzqSSFtYsTNmyyV4bM-OBwhcwhy-w_HwQYmQ HTTP/1.1
Host: myserver.com:8014
User-Agent: Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:60.0) Gecko/20100101 Firefox/60.0
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8
Accept-Language: en-US,de;q=0.7,en;q=0.3
Accept-Encoding: gzip, deflate
Connection: keep-alive
Upgrade-Insecure-Requests: 1

HTTP/1.1 200 OK
Date: Wed May 30 08:31:22 CEST 2018
Server: donoa
Content-Type: application/json
Transfer-Encoding: chunked

3d
{"eventName":"OnChannelInformation","text":"Chunk started"}

262
{"eventName":"OnCallCreated","loginName":"oxe11","callRef":"1b460e5b1f3c0100","callData":{"initialCalled":{"id":{"phoneNumber":"11"}},"state":"RINGING_INCOMING","tags":[],"capabilities":{"addMedias":[],"redirect":true,"pickedUp":true,"redirectToVoiceMail":true,"terminate":true}},"legs":[{"deviceId":"11","media":"AUDIO","state":"RINGING_INCOMING","capabilities":{"answer":true}}],"participants":[{"participantId":"198","identity":{"id":{"phoneNumber":"198"},"firstName":"Raum 2.1","lastName":"Hotline","type":{"main":"EXTERNAL","subType":"pbx"}},"medias":[],"mediaCapabilities":[]}],"deviceCapabilities":[]}

148
{"eventName":"OnCallModified","loginName":"oxe11","callRef":"1b460e5b1f3c0100","modifiedLegs":[],"addedLegs":[{"deviceId":"99999851","media":"AUDIO","state":"RINGING_INCOMING","capabilities":{"answer":true}}],"removedLegs":[],"modifiedParticipants":[],"addedParticipants":[],"removedParticipantIds":[],"deviceCapabilities":[]}

以异步方式接收块数据。我想从每个块中产生一个＆＃34;事件＆＃34;反对并回调我的主要功能。

Restsharp，使用不同的JSON文档进行响应

0 个答案: